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MA_775_DIABLO [31]
4 years ago
5

Draw a number line that shows two equivalent fractions.label your number line and explain how you know the fractions are equival

ent.

Mathematics
1 answer:
Anastasy [175]4 years ago
8 0
Here is a photo of what I chose as my equivalent numbers (Red represents my work, blue represents which step comes next, and highlighter shows what the answer is). My reasoning that 1/2 and 5/10 are equivalent is because 5/10 divided by 5/5 is 1/2.

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Find the approximate value of √191 to the nearest tenth. What 2 numbers does it fall between when placed on a number line?
meriva

The approximate value of √191 to the nearest tenth is 13.8 and the two numbers that should fall on the number line is between 13-13.5.

Given that,

  • The square root of √191.

So, the approximate value of √191 is

= \sqrt{191} \\\\= 13.82\\\\

= 13.8

It shows that the two numbers that should fall between at the time when place on the number line is between 13-13.5.

Therefore we can conclude that the approximate value of √191 to the nearest tenth is 13.8 and the two numbers that should fall on the number line are between 13-13.5.

Learn more about the number line here: brainly.com/question/16191404

7 0
3 years ago
Please help, x = ? thank you!
masya89 [10]

Answer:

x = 9.8

Step-by-step explanation:

They are same shape so we just get the ratio.

AB/JK = BC/KL

5 / 7 = 7 / x

5x = 49

x = 9.8

4 0
4 years ago
Read 2 more answers
What is the value of x ???
k0ka [10]

Answer:

D. 2\sqrt {133}

Step-by-step explanation:

{x}^{2}  =  {18}^{2}  + ( {12}^{2}  +  {8}^{2} ) \\  \\  {x}^{2}  = 324 + (144 + 64) \\  \\  {x}^{2}  = 324 + 204 \\  \\  {x}^{2}  = 528 \\  \\ x =  \sqrt{532}  \\  \\ x =  \sqrt{4\times 133}  \\  \\ x = 2\sqrt {133}

6 0
3 years ago
Elena has $0.90. Kia has 10 times as much money as Elena. Troy has one-tenth as much money as Elena. Does Kia have more money th
lina2011 [118]

Answer: Kia has ten times more money than Elena. Kia has more money that Elena.

Troy has one-tenth of the money Elena has. Troy has less money than Elena.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A sporting goods store believes the average age of its customers is 38 or less. A random sample of 40 customers was​ surveyed, a
pashok25 [27]

Answer:

Test statistics = 2.85

P-value = 0.002

Step-by-step explanation:

We are given that a sporting goods store believes the average age of its customers is 38 or less.

A random sample of 40 customers was​ surveyed, and the average customer age was found to be 41.6 years and the standard deviation for customer age is 8.0 years.

Null Hypothesis, H_0 : \mu <= 38 years

Alternate Hypothesis, H_1 : \mu > 38 years

The test statistics we will use here is;

                 T.S. = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean = 41.6 years

               \sigma = population standard deviation = 8 years

               n = sample size = 40

So, test statistics = \frac{41.6-38}{\frac{8}{\sqrt{40} } } = 2.85

At 5% level of significance, the z table gives critical value of 1.6449. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject the null hypothesis and conclude that average age of its customers is more than 38 years.

P-value is given by, P(Z > 2.85) = 1 - P(Z <= 2.85) = 1 - 0.99781 = 0.002 .

4 0
4 years ago
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