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weqwewe [10]
2 years ago
6

Suppose that 28.3% of all students took an accounting course 31.3 of all students took a statistics course and 49.1 of all stude

nts took in accounting and statistics course what is the probability that a randomly-selecte student took in accounting or statistics course
Mathematics
1 answer:
Zarrin [17]2 years ago
6 0

Answer:

10.5%

Step-by-step explanation:

The probability that a student took an accounting course, P(A)= 28.3%

The probability that a student took a statistics course P(A)= 31.3%

The probability that a student took accounting and statistics course,

P(A \cap S)=49.1\%

We want to determine the probability that a randomly selected student took an accounting or statistics course, P(A \cup S)

In probability theory,

P(A \cup S)=P(A)+P(S)-P(A \cap S)\\P(A \cup S)=28.3\%+31.3\%-49.1\%\\P(A \cup S)=0.283+0.313-0.491\\P(A \cup S)=0.105

The probability that a randomly selected student took an accounting or statistics course is 0.105 or 10.5%.

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Determine whether LINE AB and LINE CD are parallel, perpendicular, or neither. A(−1, −4) , B(2, 11) , C(1, 1) , D(4, 10) ( write
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Step-by-step explanation:

Hey there!

The points of line AB are; (-1,-4) and (2,11).

Note:

  • Use double point formula and simplify it to get two eqaution.
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~ Use double point formula.

(y - y1) =  \frac{y2 - y1}{x2 - x1} (x - x1)

~ Keep all values.

(y  + 4) =  \frac{11 + 4}{2 + 1} (x + 1)

~ Simplify it.

y + 4 =  \frac{15}{3} (x + 1)

y + 4 = 5x + 5

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Therefore this is the equation of line AB.

Now, Finding the equation of line CD.

Given;

The points of line CD are; (1,1) and (4,10).

~ Using formula.

(y - y1) =  \frac{y2 - y1}{x2 - x1}(x - x1)

~ Keep all values.

(y - 1) =  \frac{10 - 1}{4 - 1} (x - 1)

~ Simplify it.

y - 1 = 3 x - 3

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Therefore, 3x - y- 2 = 0 is the eqaution of line CD.

Use condition of parallel lines.

m1= m2

Slope of equation (i)

m1 =  \frac{ - coeff. \: of \: x}{coeff \: of \: y}

m1 =  \frac{ - 5}{ - 1}

Therefore, m1 = 5

Slope of second equation.

m2 =  \frac{ - coeff \: .of \: x}{coeff \: .of \: y}

m2 =   \frac{ - 3}{ - 1}

Therefore, m2 = 3.

Now, m1≠m2.

So, the lies are not parallel.

Check for perpendicular.

m1*m2= -1

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Therefore, they aren't perpendicular too.

So, they are neither.

<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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