The answer is
t dy / dt + dy / dt = te ^ y
I apply common factor 1/dt*(tdy+dy)=te^y
I pass "dt" tdy+dy=(te^y)*dt
I apply common factor (t+1)*dy=(te^y)*dt
I pass "e^y" (1/e^y)dy=((t+1)*t)*dt
I apply integrals ∫ (1/e^y)dy= ∫ (t^2+t)*dt
by property of integrals ∫ (1/e^y)dy= ∫ (e^-y)dy
∫ (e^-y)dy= ∫ (t^2+t)*dt
I apply integrals
-e^-y=(t^3/3)+(t^2/2)+C
I apply natural logarithm to eliminate "e"
-ln (e^-y)=-ln(t^3/3)+(t^2/2)+C
y=ln(t^3/3)+(t^2/2)+C
The greatest common factor for 5 and 10 is 5
Answer:
the 600 bags of cement would weigh 25.5826 tonnes
Answer:
x=−3
Step-by-step explanation:
2(6x+1)−4(x−5)=−2
Step 1: Simplify both sides of the equation.
2(6x+1)−4(x−5)=−2
(2)(6x)+(2)(1)+(−4)(x)+(−4)(−5)=−2(Distribute)
12x+2+−4x+20=−2
(12x+−4x)+(2+20)=−2(Combine Like Terms)
8x+22=−2
8x+22=−2
Step 2: Subtract 22 from both sides.
8x+22−22=−2−22
8x=−24
Step 3: Divide both sides by 8.
8x/8=−24/8
You could have 34,884 desserts.
The fundamental counting principle says that to find the total we do choices x choices x choices....
In this case, we have 969*12*3 = 34884.