Answer:
See explanation
Step-by-step explanation:
<h3 /><h3>Step 1</h3>
Miguel wins $2 is if he pulls two chips with the number 1.
<u>Probability of winning is:
</u>
- 2/4 * 1/3 = 1/6 as there are 4 chips in total
<u>
Probability of loosing is:</u>
<h3 /><h3>Step 2</h3>
<u>Missing values we found in the step 1, can be populated in the table:</u>
- Xi === 2 === -1
- P(Xi) === 1/6 === 5/6
<u>Expected Value as per table data:</u>
Expected value is $1/2 loss each time he plays
<h3 /><h3>Step 3</h3>
To make the game fair, the expected value should be zero.
<u>Then as per the calculation above, let's replace 2, with x, and find its value.</u>
- 1/6x + 5/6*(-1) = 0
- 1/6x = 5/6
- x= 5
So the amount should be $5 to make the game fair.
Answer:
X equals to -11
Step-by-step explanation:
Answer:
Step-by-step explanation:
10 contain both chocolate and caramel
There are 18 candies.
3 don't contain either chocolate or caramel
12 contain chocolate.
There are 18 - 12 - 3 that are not accounted for. So we have 3 that are not mentioned. Those 3 must contain just caramel.
So it should be filled out like this
contain caramel Do not contain Caramel
10 2
3 3
Answer:
a1 = 6
a2 = 15
a3 = 24
a4 = 33
Step-by-step explanation:
Let k =1
a1 =-3 +9(1) = -3 +9 = 6
Let k = 2
a2 = -3 +9(2) =-3+18 = 15
Let k =3
a3 =-3 +9(3) = -3 +27 = 24
Let k = 4
a4 = -3 +9(4) =-3+36 = 33
