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Alexeev081 [22]
4 years ago
7

I'm working on graphing functions my problem is h (x)=(x-5)^2

Mathematics
1 answer:
zlopas [31]4 years ago
7 0
H(x) = (x - 5)²
h(x) = (x - 5)(x - 5)
h(x) = x(x - 5) - 5(x - 5)
h(x) = x(x) - x(5) - 5(x) + 5(5)
h(x) = x² - 5x - 5x + 25
h(x) = x² - 10x + 25

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Bearing is a topic that can be used to <u>locate</u> the <em>position</em> of an object at a given time. Therefore, the blimp is <em>80 m</em> far away from its <u>starting</u> point. And in the<em> North-East </em>direction.

The <u>speed</u> of an object relates the <em>distance</em> it covers to the <u>time taken</u> to cover the said distance.

i.e speed = \frac{distance}{time taken}

⇒ distance = speed x time taken

In the given question, the <u>initial</u> distance covered can be determined as;

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The<u> final </u>distance covered can be determined as;

distance = 40 mph x 1 h

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Let the <u>distance</u> from its <em>starting</em> point to its <em>fina</em>l location be represented by x.

Thus applying the<em> Cosine rule</em>, we have:

c^{2} = a^{2} + b^{2} - 2abCos C

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x = \sqrt{6400}

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x = 80 m

Therefore, the <u>distance</u> of the blimp from its <em>starting</em> point to its <em>final</em> destination is <u>80 m</u>.

For more clarifications on bearings, visit: brainly.com/question/22979472

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