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ratelena [41]
3 years ago
15

Solve for y: -1/2 = 3/8y y=?

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
8 0

Answer:

y=-4/3

Step-by-step explanation:

You might be interested in
Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the
KiRa [710]

Answer:

395, 17.212

(360.576,429.424)

Step-by-step explanation:

Given that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p.

Here n=1580and p =1/4 =0.25\\q = 0.75\\np = 395 and\\nq = 1185

Since np and nq are greater than 5 by rule of thumb we can approximate binomial to normal.

Mean = np = 395

Variance = npq = 395*0.75=296.25

Std dev = 17.212

Thus X no of successes is N(395, 17.212)

THe the minimum usual value mu minus 2 sigma and the maximum usual value mu plus 2 sigma would be

395-2(17.212), 395+2(17.212)\\= 360.576,429.424

8 0
3 years ago
CORRECT ANSWER= BRAINLIEST
tangare [24]

Answer:

17 meters

Step-by-step explanation:

I did 16^2 and 7^2 to get, 256 + 49 = 305. 305 squared is 17.4... Once you round it you should get the answer 17 meters.

Hope this helps :)

6 0
3 years ago
Read 2 more answers
Tom and his friend are driving to Tameka is taking the same 432-mile round trip as Tom to Louisville, but renting a car at a spe
timurjin [86]

Answer: The correct answer is $ 134.42 for the gas and the rental.

Step-by-step explanation: The trip is 432 miles and Tameka's car gets 35 miles to the gallon. So we have to figure out how many gallons we would use for the entire trip by dividing 432 by 35= 12.34 gallons of gas.

We know gas is $2.79 a gallon so we multiply 2.79 (cost per gallon) x 12.34 ( our total gallons used) =$34.43 in gasoline.

The rental costs $99.99 so we add that cost and the cost of the gas $34.43= $134.42 the total cost of the rental and the gas.

3 0
4 years ago
A car travels at 49 km/hour how far does it travel in a 12 hour day​
marta [7]

Answer:   2.88 km.

Step-by-step explanation:

We will discuss here how to find the distance when speed and time are given.

When speed and time are given, the distance travelled is calculated by using the formula:

Distance = Speed × Time

The unit of time in speed should be the same as that of the given time.

Solved examples to calculate distance when speed and time are given:

1. How much distance will be covered in 5 hrs at a speed of 55 km per hour?

Solution:

Distance covered in 1 hour = 55 km.

We know, Distance = Speed × Time

Distance covered in 5 hrs = 55 × 5

                                  = 275 km.

Therefore, distance covered in 5 hrs = 275 km.

2. A bus travels at a speed of 45 km/hour. How far will it travel in 36 minutes?

Solution:

Speed = 45 km/hour

Time = 36 minutes

      = 36/60 Hour (Since we know, 1 hour = 60 minutes)

      = 3/5 hour

Distance = speed × time

           = 45 × (3/5) km

           = (45 × 3)/5 km

           = 27 km.

3. How much distance will be covered in 7 hrs at a speed of 62 km per hour?

Solution:

Distance covered in 1 hour = 62 km.

We know, Distance = Speed × Time

Distance covered in 7 hrs = 62 × 7

                                     = 434 km.

Therefore, distance covered in 7 hrs = 434 km.

4. Mike drives his car at a speed of 70 km per hour. How much distance will he cover in 3 hours 30 minutes?

Solution:

Speed of the car = 70 km/hr

Time taken         = 3 hours 30 minutes

                        = 3 ½ hours.

Distance covered in 1 hour = 70 km

Distance covered in 3 ½ hour = 70 × 3 ½ km

                                          = 70 × 7/2 km

                                          = 245 km.

5. How much distance will be covered in 1 ½ hour at a speed of 32 m per minute?

Solution:

[1 ½ hr = (60 + 30) minutes = 90 minutes].

Distance covered in 1 minute = 32 metres.

Distance covered in 90 minutes = 32 × 90 = 2880 m.

We know, 1 m = 1/1000 km.

                     = 2880/1000 km.

                     = 2.88 km.

Hope this helps!

5 0
2 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 447 gram setting. It is
lord [1]

Answer:

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 447 gram setting.

H_0:\mu = 447\\H_a:\mu\neq 447

Mean = \mu = 447\\s = 21\\x = 443

n = 19

Since n < 30 , so we will use t test

t=\frac{x-\mu}{\frac{s}{\sqrt{n}}}

Substitute the values :

t=\frac{443-447}{\frac{21}{\sqrt{19}}}

t=−0.8302

t calculated = -0.830

degree of freedom = n-1 = 19-1 = 18

A level of significance=α=0.025

t_{(df,\frac{\alpha}{2})}=2.093

t critical = 2.093

t calculated < t critical

So, We failed to reject null hypothesis

Decision rule  -0.830< 2.093 So, We failed to reject null hypothesis

4 0
3 years ago
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