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3 years ago

-0.38 (8 repeating) written as a fraction is _____.

Mathematics

2 answers:

natulia [17]3 years ago

7 0

Answer:

$\frac{7}{18}$

Step-by-step explanation:

We first let 0.38 (8 being repeated) be T.

Since z is recurring in 1 decimal places, we multiply it by 10. 10z = 3.88

Next, we subtract them. 10 r T 3.88 0.38 9x 3.5

Lastly, we divide both sides by 9 to get IC as a fraction. 3.5 T 9 35 90 7 18

Nesterboy [21]3 years ago

7 0

Answer:⁷/18

Step-by-step explanation

Make the repeating number as x

Since x is repeated in one decimal place multiple it by 10

10x=3.888

Next we subtract them

10x-1x=9x

0.38-3.88=3.5

9x=3.5

We divide both sides by 9

9x÷9=3.5÷9

X=⁷/18

Answer =⁷/18

Hope I was of help

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2 years ago

write the logarithm as a sum or difference of logarithms. simplify each term as much as possible. log4(6ab)

Dominik [7]

The logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

$log_{4 }6ab$

This can be written as

$log_{4 }6 \times a \times b$

From one of the rules of logarithm, we have that

$log_{x }yz= log_{x }y + log_{x }z$

Thus,

$log_{4 }6 \times a \times b$ becomes

$log_{4 }6 + log_{4 }a + log_{4 }b$

This can be further simplified into

$log_{4 }3 \times 2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b$

If desired, this can be further simplified into

$log_{4 }3 + log_{2^{2} }2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b$

$\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Hence, the logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Learn more on Simplifying logarithms here: brainly.com/question/17851187

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