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3 years ago

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A factory uses 15 pounds of steel for every 18 pounds of copper. How much copper will the factory use for 2,700 of steel. A.2,25

0lbs B.2,400lbs C.3,240lbs D.3,700lbs?

1 answer:

Orlov [11]3 years ago

7 0

Your answer is C.3,240 Ibs

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In scientific notation

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The answer is 5 x 10*3

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2 years ago

Find the complement of an angle whose measure is 74 degrees. Show all work.

Ray Of Light [21]

Answer:
angle = 16°

Explanation:
Complementary angles are angles that add up to 90°
Assume that the angle that we are looking for is x.
Based on the definition of the complementary angles, the equation will be as follows:
x + 74 = 90
Now, we will simply solve for x as follows:
x = 90 - 74
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Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

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2 years ago

A and B someone can help ny plis

kolezko [41]

Answer:

Part A: 15 and 100 are the coefficients!

Part B: Two terms in the expression!

Step-by-step explanation:

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3 years ago