Answer:
The probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5
Step-by-step explanation:
We are given that . At Johnson University, the mean time is 5 hrs with a standard deviation of 1.2 hrs.
Mean = 
Standard deviation = 
We are supposed to find the probability that the average time 100 random students on campus will spend more than 5 hours on the internet i.e. P(X>5)


Z=0
P(X>5)=1-P(X<5)=1-P(Z<0)=1-0.5=0.5
Hence the probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5
Step-by-step explanation:
Money in the beginning: 400$.
Money after the first raise: 400$+5%*400$=420$
5%*400= 5*400/100=20$
The second raise is applied on the money AFTER THE FIRST RAISE.
420$+6%*420=445.2$
6%*420= 420*6/100 = 25.2$
270 centimeters use
k
h
d
u
d
c
m
Answer:
1/2
Step-by-step explanation:
y=mx+c
so by comparing the two m=1/2
Answer:83°
Step-by-step explanation:
43+x=126
x=126-43
x=83