Answer:
Sides: a = 122 b = 122 c = 122
Area: T = 6444.961
Perimeter: p = 366
Semiperimeter: s = 183
Angle ∠ A = α = 60° = 1.047 rad
Angle ∠ B = β = 60° = 1.047 rad
Angle ∠ C = γ = 60° = 1.047 rad
Height: ha = 105.655
Height: hb = 105.655
Height: hc = 105.655
Median: ma = 105.655
Median: mb = 105.655
Median: mc = 105.655
Inradius: r = 35.218
Circumradius: R = 70.437
Vertex coordinates: A[122; 0] B[0; 0] C[61; 105.655]
Centroid: CG[61; 35.218]
Coordinates of the circumscribed circle: U[61; 35.218]
Coordinates of the inscribed circle: I[61; 35.218]
Exterior (or external, outer) angles of the triangle:
∠ A' = α' = 120° = 1.047 rad
∠ B' = β' = 120° = 1.047 rad
∠ C' = γ' = 120° = 1.047 rad
Step-by-step explanation:
Answer:

Step-by-step explanation:

substitute (1) to (2):
add x to both sides

subtract 5 from both sides


substitute the values of x to (2):

Answer:
a)1750
b)1655
Step-by-step explanation:
(1.75*1000)-95=1655
Answer:
the answer is c
Step-by-step explanation:
Round pan volume is:
3.14•r^2•h
D=7 so r=3.5 in
3.14• (3.5^2)•2 = 76.97 in^3
Rec. pan vol. is :
9•6•2= 108 in^3
Rec. Pan is larger because 108 in^3 is > 76.97 in^3 :) .
The icing that will be needed to frost the round cake pan is:
We need to find the surface area:
S.A= 3.14r^2 + 2 • 3.14•r • h .... 3.14 is the value of PI
So, S.A= 3.14• 3.5^2 + 6.28• 3.5• 2= 82.47 in^2 the icing that'll be needed to frost the round cake pan.
Icing that will be needed for the rec. cake pan is:
2•9•2=36 in^2
6•9•2= 108in^2
6•2= 12 in^2
S.A= 156 in^2 the icing needed to frost the rec. cake pan .... the S.A of all sides except the bottom one :).
Good luck ;-)