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chubhunter [2.5K]
3 years ago
12

Using a calculator, find the decimal equivalent for the fraction 416888 416 888 . CLEAR CHECK 0.468⎯⎯ 0 . 46 8 ¯ 0.468 0 . 468 0

.467 0 . 467 0.468⎯⎯⎯⎯⎯⎯
Mathematics
2 answers:
vlabodo [156]3 years ago
8 0
<h3>Decimal equivalent for the fraction can be written as \overline{0.468468}</h3>

Step-by-step explanation:

Here, the given fraction that needs to be divided is:

P = (\frac{416}{888} )

Now, here the dividend is given as : 416

The Divisor is given as: 886

Also, as Divisor > Dividend

⇒ <u>The quotient will be less than 1.</u>

Now, if we use the calculator to find the decimal equivalent of P , we get:

P = (\frac{416}{888} )  = 0.4684684684..

Noe, as we can see, the group number (468468) is repeated non terminating.

So, the solved quotient can be written as : \overline{0.468468}

Hence, decimal equivalent for the fraction can be written as \overline{0.468468}

Oduvanchick [21]3 years ago
4 0

Answer:0\overline{.468}

Step-by-step explanation:

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A triangle with one angle that measures 122 is considered blank
Ksenya-84 [330]

Answer:

Sides: a = 122   b = 122   c = 122

Area: T = 6444.961

Perimeter: p = 366

Semiperimeter: s = 183

Angle ∠ A = α = 60° = 1.047 rad

Angle ∠ B = β = 60° = 1.047 rad

Angle ∠ C = γ = 60° = 1.047 rad

Height: ha = 105.655

Height: hb = 105.655

Height: hc = 105.655

Median: ma = 105.655

Median: mb = 105.655

Median: mc = 105.655

Inradius: r = 35.218

Circumradius: R = 70.437

Vertex coordinates: A[122; 0] B[0; 0] C[61; 105.655]

Centroid: CG[61; 35.218]

Coordinates of the circumscribed circle: U[61; 35.218]

Coordinates of the inscribed circle: I[61; 35.218]

Exterior (or external, outer) angles of the triangle:

∠ A' = α' = 120° = 1.047 rad

∠ B' = β' = 120° = 1.047 rad

∠ C' = γ' = 120° = 1.047 rad

Step-by-step explanation:

3 0
3 years ago
PLEASEEE HELP MEEEE<br><br>NO LINKSSS
Artemon [7]

Answer:

\huge\boxed{(2,\ 3);\ (-1,\ 6)}

Step-by-step explanation:

f(x)=x^2-2x+3\to y=x^2-2x+3\\f(x)=-x+5\to y=-x+5\\\\\left\{\begin{array}{ccc}y=x^2-2x+3&(1)\\y=-x+5&(2)\end{array}\right

substitute (1) to (2):

x^2-2x+3=-x+5     add x to both sides

x^2-2x+x+3=-x+x+5

x^2-x+3=5        subtract 5 from both sides

x^2-x+3-5=5-5

x^2-x-2=0\\\\x^2+x-2x-2=0\\\\x(x+1)-2(x+1)=0\\\\(x+1)(x-2)=0\iff x+1=0\ \vee\ x-2=0\\\\\boxed{x=-1\ \vee\ x=2}

substitute the values of x to (2):

x=-1\\\\y=-(-1)+5=1+5=6\\\\\huge\boxed{(-1,\ 6)}\\\\x=2\\\\y=-2+5=3\\\\\huge\boxed{(2,\ 3)}

3 0
3 years ago
The Sunrise Café gets tea bags in boxes of 1,000. If the café charges $1.75 for each cup of tea, and each cup of tea gets one te
iren2701 [21]

Answer:

a)1750

b)1655

Step-by-step explanation:

(1.75*1000)-95=1655

7 0
4 years ago
What is the next step in the given proof? Choose the most logical approach.
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Answer:

the answer is c

Step-by-step explanation:

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3 years ago
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When baking a cake, you have a choice of the following pans: a round cake pan that is 2 inches deep and has a 7 inch diameter a
ruslelena [56]
Round pan volume is:
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D=7 so r=3.5 in
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Rec. pan vol. is :
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Rec. Pan is larger because 108 in^3 is > 76.97 in^3 :) .

The icing that will be needed to frost the round cake pan is:
We need to find the surface area:
S.A= 3.14r^2 + 2 • 3.14•r • h .... 3.14 is the value of PI
So, S.A= 3.14• 3.5^2 + 6.28• 3.5• 2= 82.47 in^2 the icing that'll be needed to frost the round cake pan.

Icing that will be needed for the rec. cake pan is:

2•9•2=36 in^2
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6•2= 12 in^2
S.A= 156 in^2 the icing needed to frost the rec. cake pan .... the S.A of all sides except the bottom one :).

Good luck ;-)

8 0
3 years ago
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