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Andreas93 [3]
4 years ago
9

Find the range of the function y= 1/2x +3 when the domain is {-2, 0, 2, 4}

Mathematics
1 answer:
Darya [45]4 years ago
8 0

Answer:

{2, 3, 4, 5}

Step-by-step explanation:

Note before I start: You probably meant to say x/2+3, so I will do this only.

Plug the values in.

You will get 2, 3, 4, and 5.

The range is just these values, so the answer is {2, 3, 4, 5}

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X/3+10=15 I don't know how to solve this I'm confused and don't know where to start
NARA [144]
X/3 +10=15
         -10   -10
x/3       =5

so the x will be 15 because if you multiply 3x5 = 15

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Data represented by quantities is called data.
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Walter’s history test scores and Janine’s history test scores are shown on the dot plot below.
Usimov [2.4K]
Hiya!

Right now, both of their medians are 86. This means that both will get the same median if a 65 was added.

I believe A.) would be the correct answer, given it's pretty far away from 83 or 84. My second answer would be B.), but I'm not sure.

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5 0
3 years ago
Read 2 more answers
What is the measure of each angle?
Elza [17]

Answer:

The measure of the angles are 46, 89, and 41 degrees.

Step-by-step explanation:

In order to find this, we need to add all 3 angles together and set equal to 180. Then we can find x.

x + 2x - 3 + x - 5 = 180

4x - 8 = 180

4x = 188

x = 46

Now we can find the value of each angle using the value of x.

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x = 46

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2x - 3

2(46) - 3

92 - 3

89

Angle 3:

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3 0
3 years ago
Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data
tresset_1 [31]

Based on the information represented by the boxplot ;

  • Latasha's lowest sale amount = 50

  • Kayla's median is between 200 and 300

  • Latasha has a greater spread due to higher IQR value

1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>

  • The minimum value is denoted by the starting position of the lower whisker on a boxplot.

  • Lowest amount of sale made by Latasha = 50

2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>

  • 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

  • 50% of sales made by Kayla is between 200 and 300

  • With median sale value being 250

3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>

  • The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

  • IQR = Upper Quartile (Q3) - Lower quartile(Q1)

<u>For Latasha</u> :

  • Q3 = 450 (Endpoint of the box)
  • Q1 = 150 (starting point of the box)

  • IQR = 450 - 150 = 300

<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>

  • Q3 = 375 (Endpoint of the box)
  • Q1 = 100 (starting point of the box)
  • IQR = 375 - 100 = 275

  • Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

4 0
2 years ago
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