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deff fn [24]
3 years ago
12

Someone please help me❤️ Urgently with at least 1

Mathematics
1 answer:
Oksanka [162]3 years ago
8 0

Answer:

See step-by-step explanation

Step-by-step explanation:

Question 3: (4, -3)

Solving through elimination: Multiply the first equation by -3.

-3x+6y=-30

3x-5y = 27

Add. The x drops out.

y= -3

Substitute -3 in for y.

x-2y=10

x-2(-3)=10

x+6=10

x=4

Question 4: (2,5)

Solve through elimination: Multiply the second equation with 3.

\frac{3}{2} x+y=8

\frac{9}{4} x-y=-\frac{1}{2}

3/2= 6/4

15/4x=7.5

x=2

3/2 (2) + y = 8

3+ y =8

y=5

Question 5: (6,4)

Use your graph to graph.

y=-\frac{1}{3} x+6

Slope of -1/3

Y-intercept of 6 (0,6)

X-intercept of 18 (18,0)

y=\frac{3}{2} x-5

Slope of 3/2

Y-intercept of -5 (0,-5)

X-intercept of \frac{10}{3} (

Question 6: (5, -7)

Ax+2By=-41

4Ax-By=88

3A+2B(4)=-41

4A(3)-B(4)=88

Solve by substitution:

Words of encouragement:

Good luck!

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enot [183]

Answer:

Your Answer would be 30! Hope this helped!

4 0
3 years ago
Read 2 more answers
Each of six jars contains the same number of candies. Alice moves half of the candies from the first jar to the second jar. Then
tino4ka555 [31]

Answer:

The number of candies in the sixth jar is 42.

Step-by-step explanation:

Assume that there are <em>x</em> number of candies in each of the six jars.

⇒ After Alice moves half of the candies from the first jar to the second jar, the number of candies in the second jar is:

\text{Number of candies in the 2nd jar}=x+\fracx}{2}=\frac{3}{2}x

⇒ After Boris moves half of the candies from the second jar to the third jar, the number of candies in the third jar is:

\text{Number of candies in the 3rd jar}=x+\frac{3x}{4}=\frac{7}{4}x

⇒ After Clara moves half of the candies from the third jar to the fourth jar, the number of candies in the fourth jar is:

\text{Number of candies in the 4th jar}=x+\frac{7x}{4}=\frac{15}{8}x

⇒ After Dara moves half of the candies from the fourth jar to the fifth jar, the number of candies in the fifth jar is:

\text{Number of candies in the 5th jar}=x+\frac{15x}{16}=\frac{31}{16}x

⇒ After Ed moves half of the candies from the fifth jar to the sixth jar, the number of candies in the sixth jar is:

\text{Number of candies in the 6th jar}=x+\frac{31x}{32}=\frac{63}{32}x

Now, it is provided that at the end, 30 candies are in the fourth jar.

Compute the value of <em>x</em> as follows:

\text{Number of candies in the 4th jar}=40\\\\\frac{15}{8}x=40\\\\x=\frac{40\times 8}{15}\\\\x=\frac{64}{3}

Compute the number of candies in the sixth jar as follows:

\text{Number of candies in the 6th jar}=\frac{63}{32}x\\

                                                    =\frac{63}{32}\times\frac{64}{3}\\\\=21\times2\\\\=42

Thus, the number of candies in the sixth jar is 42.

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3 years ago
When a rate is simplifed so that it has a denominator of 1 unit, it is called a(n) ___________ rate.
dangina [55]

Answer:

called unit rate .

Step-by-step explanation:

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Given the following information, write the linear equation in slope-intercept form.
MakcuM [25]

Answer:

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Step-by-step explanation:

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Explain the full answer
Vilka [71]
Rememer you can do anything to an equaiton as long as you do it to both sides

and the erased answer is correct


10=-6.5+n
add 6.5 both sides
10+6.5=6.5-6.5+n
16.5=0+n
16.5=n
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3 years ago
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