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garri49 [273]
4 years ago
7

At a factory, a machine puts tops on bottles at a rate of 80 bottles per minute. How many tops can be put on bottles between 8:0

0 a.m. and 3:30 p.m.?
Mathematics
1 answer:
timama [110]4 years ago
6 0

Answer:

= 36000 caps

Step-by-step explanation:

First we need to figure out how many minutes between 8 am and 3:30 pm

There are 7 hours and 30 minutes.

1 hour = 60 minutes

Multiply each by 7

7 hours = 7*60 minutes = 420 minutes

So 7 hours 30 minutes = 420 + 30 = 450 minutes

Bottle caps = rate * minutes

                   = 80 caps/minute * 450 minutes

                    = 36000 caps


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One number is 3 times more than another number. Their sum is 20. What are the two numbers?
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3x=y
X+Y=20
5=x and 15=y are the answer. You can use elimination or substitution or guess and check!
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4 years ago
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Problems 10-14 are very confusing​
Akimi4 [234]

See the attached picture:

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3 years ago
Pls help many thanks
salantis [7]

So, let's make these two values improper fractions so they're easier to work with. 4+\frac{1}{3}=\frac{12}{3}+\frac{1}{3}=\frac{13}{3} 3+\frac{1}{2}=\frac{6}{2}+\frac{1}{2}=\frac{7}{2}

So, to get the rate he grew in those months we have:

\frac{\frac{13}{3} \text{inches}}{\frac{7}{2}\text{months}} =\frac{26\text{inches}}{21\text{months}}

And to get the rate he grew in one month we have to divide both our numerator and our denominator by 21 to get:

\frac{\frac{26}{21} \text{inches}}{\text{month}}\approx \frac{1.24\text{inches}}{\text{month}} aka he grew 1.24 inches in a month.

7 0
3 years ago
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Zaheer, a boy of height 1.5m was watching the entire programme. Initially he observed the top of the flag pole at an angle of el
7nadin3 [17]

Answer:

15.2 m

Step-by-step explanation:

You need to draw a figure. Start by drawing a horizontal segment approximately 10 cm long; that is the ground. Label the left end point A and the right endpoint B. On the right endpoint, B, go up a short 1 cm vertically. That is 1.5 m, the height of Zaheer. Label that point C. Now from that point draw a horizontal line that ends up above point A. Label that point D. Now go back to point C. Draw a segment up to the left at a 30 deg angle with CD. End the segment vertically above point D. Label that point E. That is the top of the flagpole. Draw a vertical segment down from point E through point D ending at point A. Segment AE is the flagpole. Go back to point C. Move 3 cm to the left on segment CD, and draw a point there and label it F. That is where Zaheer moved to. Now connect point F to point E. That is a 45-deg elevation to point E, the top of the flagpole.

m<EFD = 45 deg

m<EFC = 135 deg

m<FEC = 15 deg

m<ECD = 30 deg

We now use the law of sines to find EC

(sin 15)/10 = (sin 135)/EC

EC = 27.32

Because of the 30-60-90 triangle, ED = EC/2

ED = 13.66

Now we add the height of Zaheer to find AE.

13.66 + 1.5 = 15.16

Answer: 15.2 m

7 0
3 years ago
You are to give an injection of a drug. The dosage is 0.4 mg per kilogram of bod The concentration of the drug in vial is listed
kipiarov [429]

Answer:

You inject 60.9628 milliliters of dosage

Step-by-step explanation:

1 pound = 0.453592kg,

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Now we are given that The dosage is 0.4 mg per kilogram of bod

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Now we are supposed to find How many milliliters (= cc) are you to inject?

So,milliliters of dosage required to inject = \frac{30.4814}{0.5} = 60.9628

Hence you inject 60.9628 milliliters of dosage

7 0
4 years ago
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