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3 years ago

829 to the nearest hundred

Mathematics

1 answer:

tiny-mole [99]3 years ago

5 0

829 to the nearest hundred is 800.

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Solve the following system. x squared / 25 + y squared / 100 = 1 x squared + y squared = 25

umka2103 [35]

Answer :

$\frac{1}{100} (4 {x}^{2} + {y}^{2} )$

$\frac{dy}{dx} = \frac{ - x}{y}$

8 0

4 years ago

The table below shows 10 data values:

andrezito [222]

It would be d , because the lowest number which is your (min) is 72 the highest number which is your (max) is 93 . Your median would be 85 because you would add 84 & 86 and in result you would get 170 then you would divide by 2 and get 85 . Your Q1 would be 76 and your Q3 would be 91 , there is 10 numbers in total separate them (72,74,76,83,84) and (86,89,91,92,93) then find the middle number in each

Hope this helps !

7 0

3 years ago

Write the equation for Chelsea's graph in

xeze [42]

Answer:

$y=-4x+16$ .

Step-by-step explanation:

From the given graph it is clear that the y-intercept is 16.

The line passes through (-2,24) and (2,8). So, slope of line is

$Slope=\dfrac{y_2-y_1}{x_2-x_1}$

$Slope=\dfrac{8-24}{2-(-2)}$

$Slope=\dfrac{-16}{4}$

$Slope=-4$

Slope intercept form of a line is

$y=mx+b$

where, m is slope and b is y-intercept.

Substitute m=-4 and b=16 in the above equation.

$y=(-4)x+(16)$

$y=-4x+16$

Therefore, the required equation is $y=-4x+16$ .

6 0

3 years ago

Need help tremendously

Alina [70]

<span>basically since 30 minutes is half of an hour, to get to a full hour you can multiply by 2, so you do that for both, 2/3 included so you get 2/3 * 2/1 4/3 is 1 1/3</span>

5 0

4 years ago

vDetermine if a Poisson experiment is described, and select the best answer: Suppose we knew that the average number of typos in

goldenfox [79]

Answer:

probability that a randomly selected page that contains only text will contain no typos that is

P(x=0) = $e^{-0.08}$ = 0.923

Step-by-step explanation:

<u>Poisson distribution</u>:-

Explanation of the Poisson distribution :-

The Poisson distribution can be derived as a limiting case of the binomial

distribution under the conditions that

i) p is very small

ii) n is very large

ii) λ = np (say finite

The probability of 'r' successes = $\frac{e^{-\alpha }\alpha^r }{r!}$

Given the average number of typos ∝ = 0.08 per page.

probability that a randomly selected page that contains only text will contain no typos that is = $p(x=0) = \frac{e^{-0.08 }\(-0.08)^0 }{0!}$

After calculation P(x=0) = $e^{-0.08}$ = 0.923

probability that a randomly selected page that contains only text will contain no typos =0.923

5 0

3 years ago