Mia enlarged a plan for an outdoor stage. The original plan is shown below. She dilated the outdoor stage by a scale factor of 4
with the center of dilation at the origin. Which ordered pair will be the coordinates of one of the new vertices? A (2,1) B (8,16) C (32,4) D (32,16)
2 answers:
Answer:
D (32,16)
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please see the attached photo.
In the photo, the four vertices are:
(-5,4) by a scale factor of 4 (-20, 16)
(8, 4) by a scale factor of 4 (32, 16)
(-6, -2) by a scale factor of 4 (-24, -8)
(8, -2) by a scale factor of 4 (31, -8)
So only D is correct.
Hope it will find you well.
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Answer:
The rocket will reach its maximum height after 6.13 seconds
Step-by-step explanation:
To find the time of the maximum height of the rocket differentiate the equation of the height with respect to the time and then equate the differentiation by 0 to find the time of the maximum height
∵ y is the height of the rocket after launch, x seconds
∵ y = -16x² + 196x + 126
- Differentiate y with respect to x
∴ y' = -16(2)x + 196
∴ y' = -32x + 196
- Equate y' by 0
∴ 0 = -32x + 196
- Add 32x to both sides
∴ 32x = 196
- Divide both sides by 32
∴ x = 6.125 seconds
- Round it to the nearest hundredth
∴ x = 6.13 seconds
∴ The rocket will reach its maximum height after 6.13 seconds
There is another solution you can find the vertex point (h , k) of the graph of the quadratic equation y = ax² + bx + c, where h = and k is the value of y at x = h and k is the maximum/minimum value
∵ a = -16 , b = 196
∴
∴ h = 6.125
∵ h is the value of x at the maximum height
∴ x = 6.125 seconds
- Round it to the nearest hundredth
∴ x = 6.13 seconds
Fatima's claim is not supported by the table because, the distribution is skewed right, with a median of 0.4 field goal advantage.
From the table, the median position is calculated as:
The 0.2nd data falls in the 0.4 field goal category.
So, the median element is:
However, the distribution of the table are concentrated on the left.
This means that, the distribution is not uniform, instead it is skewed right.
A uniform distribution has a skewness of 0.
Hence, Fatima's claim is not supported by the table
Read more about distributions at: