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koban [17]
3 years ago
14

With the remaining 3/4 gallon of honey, Lila decided to bake some loaves of bread and several batches of cookies for her school

bake sale. The bread needed 1/6 gallon of honey and the cookies needed 1/4 gallon. How much honey was left over?
Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
4 0
Find the least common denominator for all fractions: 12

3/4 = (3*3)/(4*3) = 9/12
1/6 = (1*2)/(6*2)
1/4 = (1*3)/(4*3)

Take the converted fractions to have the honey used taken away from the original total.
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Find the slop of the line​
Goshia [24]

Answer:

5/4 is your slope.

Step-by-step explanation:

5-0= 5

4-0= 4

slope is chang in y over change in x. Your first point is (0,0) and you second is (4,5).

6 0
3 years ago
And I’m back lol. Or did I never leave to begin with?-
Marianna [84]

Answer:

61 is ur answer

Step-by-step explanation:

Since this was a 90 degree angle you would just subtract 29 from the 90 degrees and get your answer.

7 0
3 years ago
A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
Suppose that an object is dropped from a height of h meters and hits the ground with a velocity of v meters per second, Then v =
nikdorinn [45]

Answer:

80

Step-by-step explanation:

4 0
3 years ago
0.05 is 1 tenth the value of
Ganezh [65]
The answer is .5. That is the answer because .5/10 = .05.
8 0
3 years ago
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