The correct answer is Choice B: 0.3098.
To find the answer, you have to use a normal distribution table. Look up the percents for each z-score and subtract them to find the region between.
z = 1.92 the percent is 0.9726
z = 0.42 the percent is 0.6628
0.9726 - 0.6628 = 0.3098
Answer : C
we need to the value of f(–1)
Table is given in the question
From the table ,
f(x) = 4 when x= -5, that is f(-5) = 4
f(x) = 0 when x= -1, that is f(-1) =0
f(x)= -1 when x=6, that is f(6) = -1
f(x)= -3 when x=9, that is f(9) = -3
So, the value of f(–1) = 0
Answer:
a 10 yd 2ft 7 in
b 10 yd 1 ft 2 in
c 99 yd
d. 4840 sq yd 7 sq ft 119 sq in
Step-by-step explanation:
a. 2 ft. 5 in. +
9 yd. 3 ft. 2 in.
---------------------
9 yd 5ft 7 in
but 3 ft = 1yd
9 yd 5ft 7 in
+1yd - 3ft
---------------------------
10 yd 2ft 7 in
b. 4 yd. 8 in
+ 6 yd. 6 in.
----------------------
10 yd 14 in
but 12 in = 1ft
10 yd 14 in
+ 1ft - 12 in
---------------------
10 yd 1 ft 2 in
c. 29 yd. 2 ft. 11 in.
55 yd. 1 ft. 10 in.
+ 13 yd. 1 ft. 3 in.
--------------------------
97 yd 4 ft 24 in
12 in = 1ft
24 in = 2ft
97 yd 4 ft 24 in
+2ft - 24 in
--------------------------------
97 yd 6ft
3 ft = 1yd
6f = 2yd
97 yd 6ft
+2yd - 6ft
---------------------
99 yd
d. 4,839 sq. yd. 8 sq. ft. 139 sq. in.
+ 7 sq. ft. 124 sq. in.
--------------------------------------------------
4839 sq yd 15 sq ft 263 sq in
12*12 = 144 sq in = 1 sq ft
4839 sq yd 15 sq ft 263 sq in
+ 1 sq ft - 144 sq in
--------------------------------------------------
4839 sq yd 16 sq ft 119 sq in
3ft * 3 ft = 9 sq ft = 1 sq yd
4839 sq yd 16 sq ft 119 sq in
+1 sq yd - 9 sq ft
----------------------------------------------
4840 sq yd 7 sq ft 119 sq in
Answer:
Step-by-step explanation:
5x = 30
If there are 5 students in a row, find the number of rows given that the number of total students is 30.
Here 'x' represents the number of row
