All categories

4 years ago

What is the domain of range of y=-2x+3

Mathematics

1 answer:

MakcuM [25]4 years ago

3 0

Answer:

In both cases, "the set of all real numbers."

Step-by-step explanation:

y= -2x+3 is a linear function and is also a polynomial. Every polynomial has an unrestricted domain: "the set of all real numbers."

There is no restriction on y where this y= -2x+3 is concerned; y may have any value.

You might be interested in

(05.05)

Natalka [10]

Y greater than or equal to -7

3 0

3 years ago

Read 2 more answers

Yoshi is painting a large wall in the park. He measures the wall and finds that the dimensions are 4 m by 20 m. Yoshi has a can

-BARSIC- [3]

No. The area of a square/rectangle is length * height, and 4 * 20 is 80m^2. Because Yoshi has a can of paint that can cover 81m^2, and 81m^2 > 80m^2, Yoshi does NOT need to buy more paint.

8 0

3 years ago

Answer this number pattern: Last one. Really need this to be answered!<br> 1,8,27,64_,_,_

Lunna [17]

The numbers to complete the pattern are 125, 216, 343. The complete pattern is 1, 8, 27, 64, 125, 216, 343. Hope this helps.

5 0

3 years ago

Printing a newsletter cost $1.50 per copy plus $450 in printers fee. The copies are sold for $3 each. How many copies of the new

e-lub [12.9K]

1.50x + 450 = 3x
450 = 3x - 1.50x
450 = 1.50x
450/1.50 = x
300 = x

300 copies must be sold to break even

6 0

3 years ago

Read 2 more answers

Student performance across discussion sections: A professor who teaches a large introductory statistics class (197 students) wit

adell [148]

Answer:

The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.

Step-by-step explanation:

Assumptions:

1. The sampling from the different discussion sections was independent and random.

2. The populations are normal with means and constant variance

$H_0:$ There's no variation among the discussion sections

$H_1:$ There's variation among the discussion sections

$\alpha =0.05$

Df Sum Sq Mean sq F value Pr(>F)

Section 7 525.01 75 1.87 0.99986

Residuals 189 7584.11 40.13

Test Statistic = $F= \frac{75}{40.13} =1.87$

$Pr(>F) = 0.99986$

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.

3 0

3 years ago