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2 years ago

Write the number 78 as a product of its prime factors

Mathematics

2 answers:

Gre4nikov [31]2 years ago

6 0

2/3 = .66666....
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Otrada [13]2 years ago

5 0

$78|2\\ 39|3 \\ 13|13 \\ 1 \\ \\ 78=2*3*13$

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Someone please help me

amid [387]

Answer: that is equivalent to 447

Step-by-step explanation:

5 0

2 years ago

1. 100 students who are in 9th or 10th grade were asked if they participated in at least one extracurricular activity (sports, m

Marianna [84]

I can not set up a 2 way table online but what they want is a collom of the information neatly laid out...

With the 9th graders in one collom and the 10th graders in the other

like this

                   9th grader   10th grader
# of students    32                      40
# of participated 32                      18

Draw this out with lines and it will be correct.

I hope this helps GOOD LUCK...this is tough math for a middle schooler.

5 0

2 years ago

A random sample of size n1= 25, taken from a normal population with a standard deviation σ1= 5, has a mean X1= 80. A second rand

sesenic [268]

Answer:

The 94% confidence interval would be given by $2.898 \leq \mu_1 -\mu_2 \leq 7.102$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =80$ represent the sample mean 1

$\bar X_2 =75$ represent the sample mean 2

n1=25 represent the sample 1 size

n2=36 represent the sample 2 size

$\sigma_1 =5$ sample standard deviation for sample 1

$\sigma_2 =3$ sample standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =80-75=5$

Since the Confidence is 0.94 or 94%, the value of $\alpha=0.06$ and $\alpha/2 =0.03$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.03,0,1)".And we see that $z_{\alpha/2}=1.88$

The standard error is given by the following formula:

$SE=\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}$

And replacing we have:

$SE=\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=1.118$

Confidence interval

Now we have everything in order to replace into formula (1):

$5-1.88\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=2.898$

$5+1.8\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=7.102$

So on this case the 94% confidence interval would be given by $2.898 \leq \mu_1 -\mu_2 \leq 7.102$

7 0

2 years ago

Carla earns $13 an hour cleaning house. How much will she earn if she works from 8:00 to 2:00?

Andreyy89

8pm to 2am, or 8am to 2pm, either way, Carla would've worked for 6 hours.

6*$13=$78

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Carla would earn $78 if she were to clean for 6 hours.

4 0

2 years ago

Read 2 more answers

What is the slope of the line?<br> m =

monitta

Answer:

m=0.25

Step-by-step explanation:

m = (y_2-y_1)/ (x_2-x_1)

Let's get 2 of any coordinates in the graph, for example: (4,2) and (0,1)

m = (1-2)/(0-4) = 1/4 or 0.25

8 0

2 years ago