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We are asked to find the two integers, given that they are consecutive, and their sum is 65.
- Consecutive integers are right next to each other, like 12 and 13. or 65 and 66.
Let the first integer be x, and let the second integer be x+1.
Their sum is 65. Let's set up our equation:
Combine like terms:
Subtract 1 from both sides of the equal sign:
Divide both sides by 2:
To find the second integer, subtract the first integer from the sum of the two integers:
The integers are: 33 and 32.
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Answer:
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Step-by-step explanation:
tb f thg. kufc if fyi uuj
Step-by-step explanation:
Transcribed image text: Spectra Analysis 7 100 80 60 40 20 150 50 STRUCTURE 60 40 20 0 180 160 140 120 100 8O
Answer:
Step-by-step explanation:
lets say "a" for the empty line,
for small triangle; y^2 = 2^2 + x^2
right triangle; we say a for empty line, a^2= 6^2 + x^2
and big triangle covering both triangles, 8^2 = y^2 + a^2
lets add left sides and right sides in each;
x^2 + 4 + x^2 + 36 + y^2 + a^2 = y^2 + a^2 + 64 and we can delete same things for both sides
y^2 and a^2 can be deleted and 4+36 - 64
2(x^2)=24
x^2= 12
and x will be √12
so, y^2 = x^2 + 2^2 which means y^2 = 12+4 y=16