Answer:
y=4x-4
slope of the line=-4/-1
4/1
since perpendicular,
m1.m2=-1
4.m2=-1
m2=-1/4
The equation of line passing through the point (4,2)is
y-y1=m2(x-x1)
y-2=-1/4(x-4)
Step-by-step explanation:
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Answer:
I can't answer this unless you give more information to the question.
I am all yours, just reply with the expression.
I believe C. The temperature is -23 degrees.
This is because, a negative (absolute value) becomes positive
Which would lead for |-23| to end up being |23|
Anytime a negative absolute value is placed, it becomes a positive and a positive stays positive.
So the smallest would be C then B later D and at last A
The unit normal for the given plane is <5,2,-1>.
The equation of the plane parallel to the given plane passing through (5,5,4) is therefore
5(x-5)+2(y-5)-1(z-4)=0
simplify =>
5x+2y-z=25+10-4=31
Answer: the plane through (5,5,4) parallel to 5x+2y-z=-6 is 5x+2y-z=31
