Answer:
y=12
Step-by-step explanation:
This equation cannot be simplified further.
Hope this helped! :)
Answer:
The signal would have experienced aliasing.
Step-by-step explanation:
Given that:
the bandwidth of the signal
= 36MHz
= 36 × 10⁶ Hz
The sampling frequency
= 36 × 10⁶ Hz
Suppose the sampling frequency is equivalent to the bandwidth of the signal, then aliasing will occur.
Therefore, according to the Nyquist criteria;
Nyquist criteria posit that if the sampling frequency is more above twice the maximum frequency to be sampled, a repeating waveform can be accurately reconstructed.
∴
By Nyquist criteria, for perfect reconstruction of an original signal, i.e. the received signal without aliasing effect;
Then,

∴
The signal would have experienced aliasing.
The 3rd one because the rest you would have to distribute them and for the 3rd one it’s the same
We can get the 5 fractions by multiplying 8/5 by 2, 3, 4, 5, and 6.
8/5*2=16/5
8/5*3=24/5
8/5*4=32/5
8/5*5=40/5 or 8.
8/5*6=48/5.
Hope this helps!
-Raiden
Answer:
15,136 hands off with cards contain exactly three queens and three jacks.
Step-by-step explanation:
The order in which the cards are chosen is not important, which means that the combinations formula is used to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
Standard deck:
4 queens and 4 jacks.
The other 52 - 8 = 44 cards are neither queens nor jacks.
Wow many hands off with cards contain exactly three queens and three jacks?
3 queens from a set of 4.
3 jacks from a set of 4.
2 other cards(not queens neither jacks) from the other 44. So

15,136 hands off with cards contain exactly three queens and three jacks.