Question

The displacement (in meters) of a particle moving in a straight line is given by the equation of motion

Answer 1

Answer:

Step-by-step explanation:

the displacement of the particle is given by

$s=\frac{9}{t^{2}}$

The rate of change of position gives the value of velocity.

So, v = ds/dt

Differentiate the position function with respect to time.

$v = ds/dt=9(-2)t^{-3}=-18t^{-3}$

Now, at t = a

v = -18/a³ m/s

At t = 1

v = - 18 m/s

At t = 2

v = - 18 / 8 = - 2.25 m/s

At t = 3

v = - 18 / 27 = 0.67 m/s