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Gekata [30.6K]
3 years ago
15

Juan Garza invested $112,000 10 years ago at 8 percent, compounded quarterly. How much has he accumulated? Use Appendix A for an

approximate answer but calculate your final answer using the formula and financial calculator methods. (Do not round intermediate calculations. Round your final answer to 2 decimal places.)
Business
1 answer:
jasenka [17]3 years ago
3 0

Answer:

$247,300

Explanation:

Given that

Invested amount = Present value = $11,2000

Time = 10 years × 4 quarter = 40

The rate = 8% ÷ 4 = 2%

So, we have to applying the future value formula which is presented below:

Future value = Present value × (1 + interest rate)^ time period

                      = $112,000 × (1 + 0.02)^40

                      = $112,000 × 1.02^40

                      = $112,000 ×2.2080396636

                      = $247,300

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Whick of the following terms applies to the way that society as a wholr earns and spends money?
VikaD [51]
It's impossible to choose a correct option as you've not attached any of it. Anyway I think that you mean the term which is called <span>APPROVED BUDGET.</span>
8 0
3 years ago
An appliance repair shop buys and uses about 4,212 fan motors annually. Holding cost is 27 dollars per motor per year, and order
Juli2301 [7.4K]

Answer:

15,251 units

Explanation:

The formula for Economic order quantity is;

EOQ = √2DS/H

Where,

D = Annual demand = 4,212

S = Ordering cost = $177

H = Holding cost = $27/4,212 = $0.00064102564

EOQ = √ 2 × 4,212 × $177 / $0.00064102564

EOQ = √ $1,491,048 / $0.00064102564

EOQ = √232603488.37

EOQ = 15,251 units

4 0
3 years ago
Equipment purchased at the beginning of the fiscal year for $150,000 is expected to have a useful life of 5 years, or 15,000 ope
CaHeK987 [17]

Answer:

(a). Depreciation for 1st year= $24,000

Depreciation for 2nd year= $24,000

(b). 1st Year Depreciation = $20,000

for 2nd year depreciation = $26,000

(c) 1st year Depreciation= $60,000

2nd year Depreciation = $36,000

Explanation:

a).

Annual Depreciation of Equipment = (Cost of Equipment - Residual Value) ÷ Useful Life of Equipment

= ($150,000 - $30,000) ÷ 5

= $24,000

Rate of Straight Line Depreciation = Annual Depreciation of Equipment ÷ (Cost of Equipment - Residual Value) × 100

= 24,000 ÷ ( $150,000 - 30,000) × 100

= $24,000 ÷ $120,000 × 100 = 20%

Depreciation for 1st year= $24,000

Depreciation for 2nd year= $24,000

b). Unit Of Production For 1st Year Depreciation= (Cost Of Equipment -Residual Value) × Annual Production Units ÷ Total Operating Hours

= ($150,000 - $30,000) × 2,500 ÷ 15,000 = $20,000

Unit of Production for 2nd year depreciation = ( $150,000 - $30,000) × 32,50 ÷ 15,000

= $26,000

c). Declining Balance Depreciation Rate = Straight Line Depreciation Rate × 2

= 20% × 2 = 40%   (Because Declining Balance at Twice the Straight Line Rate)

1st year Depreciation= $150,000 × 40÷100 = $60,000

2nd year Depreciation = ($150,000 - $60,000) × 40÷100 =$36,000

8 0
3 years ago
How does capital play an important role in the other factors of production?
OverLord2011 [107]

Answer:

Capital is an important factor of production because it's what allows labor and land to be purchased.

Explanation:

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7 0
3 years ago
Read 2 more answers
20. WACC and NPV [LO3, 5] Sommer, Inc., is considering a project that will result
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Sommer Inc is considering the new project, and yet we have to calculate under what circumstances the company have to take on the project. In order to assess the project, we need to compute the break-even cost such as the present value of future cash flows and calculate the WACC weighted cost of capital. It measures the weighted cost of equity and the after tax cost of debt. The following information are given: Debt to equity ratio = 0.90 Cost of equity = 13% After-tax cost of debt = 4.8% After-tax cost of savings = $2.7 million Debt to equity ratio = Debt / Equity = 0.90 Therefore, Value of firm = value of debt + value of equity Value of firm = 0.90E + E Value of firm

See the calculation of WACC as attachment
8 0
3 years ago
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