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kkurt [141]
3 years ago
8

Fred is 58 yes old, and Irene is 18. How many years ago was Fred 5 times as old as Irene. Algebra must be used

Mathematics
1 answer:
Sedaia [141]3 years ago
3 0
So let's take a peek at both's ages, keep in mind, every year, is 1year added to Irene and 1year added to Fred
so... if we look at their ages  \bf \begin{array}{ccllll}
fred&irene\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
58&18\\
57&17\\
56&16\\
55&15\\
...&...
\end{array}

notice, Fred is always 40years older than Irene

thus, whatever age Irene is, let's say "i", then Fred is " i + 40 "

now, when is Fred 5 times Irene's age or 5*i or 5i? well, 

f = fred's age    i = irene's age

f = i + 40
now if  f = 5i

5i = i + 40   <---    solve for "i" to see how old Irene was then
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Answer:

D. 0.9938.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 115 and a standard deviation of 8.

This means that \mu = 115, \sigma = 8

100 people are randomly selected

This means that n = 100, s = \frac{8}{\sqrt{100}} = 0.8

Find the probability that their mean blood pressure will be less than 117.

This is the p-value of Z when X = 117, so:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{117 - 115}{0.8}

Z = 2.5

Z = 2.5 has a p-value of 0.9938, and thus, the correct answer is given by option D.

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Step-by-step explanation:

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Which situation represents a proportional relationship?
Natalka [10]

Answer:

B) Jack biked 5 miles in 25 minutes and 8 miles in 40 minutes.

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y=kx

The ratio between the two variables is a constant called constant of proportionality k

k=y/x

<u><em>Verify each case</em></u>

A) Julie sold 4 necklaces for $12 and 9 necklaces for $25.

\frac{4}{12}=\frac{9}{25}

Multiply in cross

4(25)=9(12)\\100\neq108

Is not true

therefore

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B) Jack biked 5 miles in 25 minutes and 8 miles in 40 minutes.

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Multiply in cross

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Is true

therefore

The situation represent a proportional relationship

C) Larry packed 24 apples in 6 boxes and 46 apples in 9 boxes

\frac{24}{6}=\frac{46}{9}

Multiply in cross

24(9)=46(6)\\216\neq276

Is not true

therefore

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Multiply in cross

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The situation not represent a proportional relationship

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