Find the value of n 2k

I need help please.

makkiz [27]

Answer:

see explanation

Step-by-step explanation:

Using the rules of radicals/ exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$

$a^{\frac{m}{n} }$ ⇔ $\sqrt[n]{a^{m} }$

Simplifying each term

7 $\sqrt{x^{3} }$ = 7 $x^{\frac{3}{2} }$

x $\sqrt{9x}$

= x × $\sqrt{9}$ × $\sqrt{x}$

= x × 3 × $x^{\frac{1}{2} }$

= 3 × $x^{(1+\frac{1}{2}) }$

= 3 $x^{\frac{3}{2} }$

Subtracting the 2 simplified like terms, that is

7 $x^{\frac{3}{2} }$ - 3 $x^{\frac{3}{2} }$

= 4 $x^{\frac{3}{2} }$ ← return to radical form

= 4 $\sqrt{x^{3} }$

8 0

3 years ago

Mark is buying a game from an online store. He has not heard of the store or the online payment service before, but the price is

Semenov [28]

It could be B but I want to say D because it relates more to the question.

3 0

3 years ago

Sin4x.sin5x+sin4x.sin3x-sin2x.sinx=0

andreev551 [17]

Recall the angle sum identity for cosine:

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

cos(x - y) = cos(x) cos(y) + sin(x) sin(y)

==> sin(x) sin(y) = 1/2 (cos(x - y) - cos(x + y))

Then rewrite the equation as

sin(4x) sin(5x) + sin(4x) sin(3x) - sin(2x) sin(x) = 0

1/2 (cos(-x) - cos(9x)) + 1/2 (cos(x) - cos(7x)) - 1/2 (cos(x) - cos(3x)) = 0

1/2 (cos(9x) - cos(x)) + 1/2 (cos(7x) - cos(3x)) = 0

sin(5x) sin(-4x) + sin(5x) sin(-2x) = 0

-sin(5x) (sin(4x) + sin(2x)) = 0

sin(5x) (sin(4x) + sin(2x)) = 0

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

Rewrite the equation again as

sin(5x) (2 sin(2x) cos(2x) + sin(2x)) = 0

sin(5x) sin(2x) (2 cos(2x) + 1) = 0

sin(5x) = 0 or sin(2x) = 0 or 2 cos(2x) + 1 = 0

sin(5x) = 0 or sin(2x) = 0 or cos(2x) = -1/2

sin(5x) = 0 ==> 5x = arcsin(0) + 2nπ or 5x = arcsin(0) + π + 2nπ

… … … … … ==> 5x = 2nπ or 5x = (2n + 1)π

… … … … … ==> x = 2nπ/5 or x = (2n + 1)π/5

sin(2x) = 0 ==> 2x = arcsin(0) + 2nπ or 2x = arcsin(0) + π + 2nπ

… … … … … ==> 2x = 2nπ or 2x = (2n + 1)π

… … … … … ==> x = nπ or x = (2n + 1)π/2

cos(2x) = -1/2 ==> 2x = arccos(-1/2) + 2nπ or 2x = -arccos(-1/2) + 2nπ

… … … … … … ==> 2x = 2π/3 + 2nπ or 2x = -2π/3 + 2nπ

… … … … … … ==> x = π/3 + nπ or x = -π/3 + nπ

(where n is any integer)

5 0

3 years ago

What is the length of the unknown side?

777dan777 [17]

Answer:

Hi there!

The correct answer is: 20

Step-by-step explanation:

knowing this a right triangle you can solve this problem in two ways

Method One: Pythagorean Theorem

a^2 + b^2 = c^2 then plug in the values

(12)^2 + (16)^2 = c^2 this will come out to be 400 = c^2

square root both sides and you get c = 20

Method Two: Pythagorean Identities

if you ever learned the Pythagorean identity 3,4,5

this triangle is indeed a 3,4,5 triangle it's just that each side is multiplied by the factor 4

so in this case since you know the missing side should be 5 you just multiply 5 by 4 and you get 20

4 0

3 years ago

Kevin has $24 to buy a gift for his cousin he found a gift for $22 with a 5% sales tax added on will Kevin have enough money to

STatiana [176]

Kevin will have enough. He will need to pay $23.10.

5% of $22 is $1.10.

22+1.10=23.10

23.10 is less than 24

6 0

3 years ago