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marusya05 [52]
3 years ago
11

What is the scientific notation for 0.000006

Mathematics
1 answer:
zaharov [31]3 years ago
3 0
6*10^-6 is the answer
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One of the more famous anecdotes in the field of statistics is known as the "Lady Tasting Tea" and involves the renowned statist
mote1985 [20]

Answer:

n=\frac{0.3(1-0.3)}{(\frac{0.01}{1.96})^2}=8067.36  

And rounded up we have that n=8068

Step-by-step explanation:

The margin of error for the proportion interval is given by this:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

We want for this case a 95% of confidence desired, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for this case is ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

The estimated proportion for this case is \hat p=0.3. And replacing into equation (b) the values from part a we got:

n=\frac{0.3(1-0.3)}{(\frac{0.01}{1.96})^2}=8067.36  

And rounded up we have that n=8068

7 0
3 years ago
Examine the following three premises: i. All kids who have a smartphone play mobile legends.
atroni [7]

Answer:

The increasing number of students who are hooked on playing online mobile games (OMG) is alarming. As such, this study was realized to address the problem. This study assessed the gaming profile towards OMG and its relation to the academic performance of the engineering students of Eastern Visayas State University Tanauan Campus (EVSUTC). Specifically, the study investigated the correlation between student's number of hours spent on playing OMG (at school and home), commonly played OMG (at school and home), reasons for playing OMG and attitudes on playing OMG with academic performance utilizing Eta and Pearson r correlation analyses. A random sample of 134 student respondents were selected through purposive sampling of those who are playing OMG using their mobile phones. Descriptive correlational research design was utilized and a validated survey instrument was employed to gather the needed information. The findings revealed that majority of the students played mobile legends and spent mostly 2 hours playing OMG for a reason of boredom. The overall attitudes of the students on playing OMG were interpreted as Less Favorable (M=2.58, SD=1.13). Out of the independent variables being set in the study, the number of hours spent on playing OMG at home (r=-0.188, p=0.039) and commonly played OMG at school (r=0.203, p=0.045) were found significantly correlated with student's academic performance. Hence, the students' time spent on playing OMG at home and the type of games that students played at school have significant bearing to their academic performance. As such, delimiting student's usage of internet can be made to address the problem.

3 0
2 years ago
The weight distribution of parcels sent in a certain manner is normal with mean of 12 lb and standard deviation of 3 lb. The par
kicyunya [14]

Answer:

21.16

Step-by-step explanation:

Starting from the theory we have the following equation:

fi*P(x

Using the data supplied in the exercise, we have subtracting the mean and dividing by the standard deviation:

P( z \leq \frac{c-1-12}{3.5}) =0.99/fi

solving for "c", knowing that fi is a tabulating value:

\frac{c-13}{3.5}=0.99/fi\\\frac{c-13}{3.5}=2.33\\c-13=2.33*3.5\\c = 8.155 +13\\c = 21.155

therefore the value of c is equal to 21.16

8 0
4 years ago
Pleaseeeeee help this is due today and I don’t know how to do thissss! Tug of War Activity
Hoochie [10]

Answer:

i

Step-by-step explanation:

7 0
3 years ago
Li transformed rectangle ABCD. The image is shown. Does Li’s transformation represent a translation? Yes, the image represents a
iris [78.8K]

Answer:

C. No, the image does not have the same orientation.

Step-by-step explanation:

Just took the quiz.

6 0
4 years ago
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