4 years ago

Solve the equation 2x^2-5x+1=0

Mathematics

1 answer:

SCORPION-xisa [38]4 years ago

3 0

Answer:

Step-by-step explanation:

$2x^2-5x+1=0\\x=\frac{5+-\sqrt{25-8} }{2*2} \\x=\frac{5+-\sqrt{17} }{4}$

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