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2 years ago

5

Stan is on a bike ride. His GPS indicates that he has traveled exactly 18 miles and he is 32% complete with his total ride. How

many miles long is Stan's ride?

1 answer:

Assoli18 [71]2 years ago

3 0

His journey is 62 miles long

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Find the slope of a line parallel to this given line

dybincka [34]

bearing in mind that parallel lines have the same exact slope, then any parallel line to the one above will have the same slope as that one.

$\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \qquad \implies y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{7}{3}}x-4$

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2 years ago

Solving Equations with the variable on each side

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Multiply both sides by 6
(b-4)/6*6= b-4
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2 years ago

(5x²+2) - (-4x²+7)+(-3x²-5)

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6x^2 -10

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(5x²+2) - (-4x²+7)+(-3x²-5)

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(5x²+2) +4x²-7 +(-3x²-5)

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5x²+4x²-3x² +2-7-5

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3 years ago

Lucia has 50 sports cards she has 20 football cards 10 baseball card 15 basketball card and five hockey cards a single card is s

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4 0

2 years ago

Read 2 more answers

Assume that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles

OverLord2011 [107]

Answer:

Final answer is approx 6.644 years.

Step-by-step explanation:

Given that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles is 16% every year and that of cars is 25% every year.

So we can use growth formula:

$A=P\left(1+r\right)^t$

Then we get equation for motorcycles and cars as:

$A=5.75\left(1+0.16\right)^t$

$A=3.5\left(1+0.25\right)^t$

Now we need to find about when the sale of cars will be more than the sale of motorcycles. So we get:

$3.5\left(1+0.25\right)^t>5.75\left(1+0.16\right)^t$

$3.5\left(1.25\right)^t>5.75\left(1.16\right)^t$

$3.5\left(1.25\right)^t>5.75\left(1.16\right)^t$

$\frac{\left(1.25\right)^t}{\left(1.16\right)^t}>\frac{5.75}{3.5}$

$\left(\frac{1.25}{1.16}\right)^t>1.64285714286$

$t\cdot\ln\left(\frac{1.25}{1.16}\right)>\ln\left(1.64285714286\right)$

$t>\frac{\ln\left(1.64285714286\right)}{\ln\left(\frac{1.25}{1.16}\right)}$

$t>6.6436473051$

Hence final answer is approx 6.644 years.

7 0

2 years ago