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gulaghasi [49]
3 years ago
7

Consider the following pair of equations:

Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0
First substitute y = x - 1 in  y = 3x + 3 , so

3x + 3 = x - 1

2x = -4

x = -2

Now substitute for x in the first equation:-

y =3(-2) + 3 = -6 + 3

y = -3 


Answer is  (-2, -3)
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Step-by-step explanation:


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PLZ HELP NO WRONG ANSWERS
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Answer :

to find area of the square = 6 to the power 2

to find the area of the rectangle = (5x + 12) * 5x

therefore,

square's area = 36

rectangle's area = 5x*5x + 12 * 5x

= 25x * 60x

Now we have to find the sum of both the areas,

so, 36 + 1500 = 1536

Step-by-step explanation:

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11-1/2y=3+6x solve for y
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11-\frac{1}{2} y=3+6x
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5 0
3 years ago
Determine whether or not 630 is a triangular number. start with the formula t n = n ( n + 1 ) 2 and then use the quadratic formu
ziro4ka [17]
Triangular sequence = n(n + 1)/2

If 630 is a triangular number, then:

n(n + 1)/2  = 630

Then n should be a positive whole number if 630 is a triangular number.

n(n + 1)/2  = 630

n(n + 1)  = 2*630

n(n + 1)  = 1260

n² + n = 1260

n² + n - 1260 = 0

By trial an error note that 1260 = 35 * 36

n² + n - 1260 = 0

Replace n with 36n - 35n

n² + 36n - 35n - 1260 = 0

n(n + 36) - 35(n + 36) = 0

(n + 36)(n - 35) = 0

n + 36 = 0   or   n - 35 = 0

n = 0 - 36,   or  n = 0 + 35

n = -36, or 35

n can not be negative. 

n = 35 is valid.

Since n is a positive whole number, that means 630 is a triangular number.

So the answer is True.
7 0
3 years ago
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