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Kamila [148]
3 years ago
12

What are the common factors of 16 and 56?

Mathematics
2 answers:
grin007 [14]3 years ago
7 0
<span>The common factors are:
1, 2, 4, 8

Hope I Helped!</span>
KonstantinChe [14]3 years ago
3 0
If I remember correctly 

16 : 1, 2 4, 8, and 16

56: 1, 2, 4, 7, 8, 14, 28, and 56. 
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You earn 360 dollars every 4 weeks how much money do you make in one week
Shtirlitz [24]

Answer:$90

Step-by-step explanation:

360/4=90

8 0
3 years ago
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Which order pair is a solution to the system of linear equations -4+y=8 and x-5y=17?
andreev551 [17]

Hello!

To find this ordered pair, we solve for x and y and put them together in an ordered pair.

-4+y=8

x-5y=17

Let's solve the first equation for y.

y= 12

Now, let's plug 12 into the second equation for y.

x-5(12)=17

x-60=17

x=77

Therefore, our ordered pair is (77,12)

I hope this helps!

4 0
3 years ago
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Suppose that the members of a student governance committee will be selected from the 40 members of the student senate. There are
Len [333]

Answer:

The total number of ways to form a student governance committee is 1,211,760.

Step-by-step explanation:

The students senate consists of a total of 40 students.

The students are either Sophomores or Juniors or Seniors.

The number of students in each of these categories are as follows:

Sophomores = 18

Juniors = 12

Seniors = 10

A governance committee have to be selected from the students senate.

The committee have to made up of 2 sophomores, 2 juniors and 3 seniors.

Combinations can be used to select 2 sophomores from 18, 2 juniors from 12 and 3 seniors from 10.

Combinations is a mathematical technique used to determine the number of ways to select <em>k</em> items from <em>n</em> distinct items.

The formula is:

{n\choose k}=\frac{n!}{k!(n-k)!}

(1)

Compute the number of ways to select 2 sophomores from 18 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{18\choose 2}=\frac{18!}{2!(18-2)!}=\frac{18\times 17\times 16!}{2\times 16!}=153

Thus, there are 153 ways to select 2 sophomores from 18.

(2)

Compute the number of ways to select 2 juniors from 12 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{12\choose 2}=\frac{12!}{2!(12-2)!}=\frac{12\times 11\times 10!}{2\times 10!}=66

Thus, there are 66 ways to select 2 juniors from 12.

(3)

Compute the number of ways to select 3 seniors from 10 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{10\choose 3}=\frac{10!}{3!(10-3)!}=\frac{10\times 9\times 8\times 7!}{2\times 3\times 7!}=120

Thus, there are 120 ways to select 3 seniors from 10.

The total number of ways to form a student governance committee that must have 2 sophomores, 2 juniors and 3 seniors is:

Total number of ways = {18\choose 2}\times {12\choose 2}\times {10\choose 3}

                                    =153\times 66\times 120\\=1211760

Thus, the total number of ways to form a student governance committee is 1,211,760.

7 0
3 years ago
Which expression is equivalent to (xy)z?
aleksandr82 [10.1K]
X/yz is the answer I believe
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A hardcover book has a mass of about 1 kilogram. What could have a mass of less than 1 kilogram? Select all that apply.
insens350 [35]
A key, pencil, and toothbrush
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3 years ago
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