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alisha [4.7K]
3 years ago
5

What order will result in a final output of 131,065 when the first input is 64

Mathematics
1 answer:
Valentin [98]3 years ago
3 0

Answer:

1. h(x) = 2ˣ-7 :  

2ˣ - 7 = 131,065  

2^x = 131,072  

x = 17  

2. k(x) = -(x/2) - 1 = 17  

x/2 = -18  

x = -36  

3. g(x) = -(x-2)² = -36  

x - 2 = 6  

x = 8  

4. f(x) = √x = 8  

x = 64  

h(k(g(f(64)))) = 131,065

Step-by-step explanation:

I hope this help

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25 miles for 1 gallon

Step-by-step explanation:

Looking at the graph, for 1 gallon of gas, is about 25 miles. For 2 gallons, it is 50 miles. For 3 gallons, it is 75 miles. So based on the graph and the pattern, we can assume 1 gallon of gas will take the car 25 miles.

5 0
2 years ago
Instructions: Rewrite the equation in proper Standard Form.
pochemuha
Standard form: x-3y=-12
3 0
3 years ago
10 pecebt in simplest form
aleksandr82 [10.1K]
10%
= 10/100
= 1/10

10% in its simplest form is 1/10~
7 0
3 years ago
(b) As in part (a), how many three-digit phone prefixes are possible that do not start with 0 or 1, but contain 0 or 1 as the mi
Lubov Fominskaja [6]

Answer:

The number of 3-digit phone prefixes that do not start with 0 or 1, but contain 0 or 1 as the middle digit is 160.

Step-by-step explanation:

The phone prefix for any area is of the form <u>X</u> <u>X</u> <u>X</u>.

These prefixes can take values from 0 to 9.

The condition to create a phone prefix is:

  • The first digit cannot be 0 or 1
  • The middle digit is either 0 or 1.

The possible number of ways to fill the first place is 8 since 0 or 1 cannot be the first digit.

The possible number of ways to fill the second place is 2 since the middle digit can be occupied by either 0 or 1.

The possible number of ways to fill the last place is 10 since there are no condition applied to the last digit.

Then the number of phone prefixes that can be formed is = 8\times2\times10=160

Thus, the possible number of phone prefixes possible is 160.

7 0
3 years ago
Airline fares for a flight from Dallas to Austin are $30 for first class and $25 for tourist class. If a flight had 52 passenger
posledela

There were 40 tourist class passengers and 12 first class passengers.  

Explanation:

Let the number of passengers who booked for tourist class be

=

x

Then, number of passengers who booked for first class

=

52

−

x

According to question,

Total money paid = $25(tourist class)+$30(first class)  

$

1360

=

$

25

(

x

)

+

$

30

(

52

−

x

)

1360

=

25

x

+

1560

−

30

x

1360

−

1560

=

25

x

−

30

x

−

200

=

−

5

x

x

=

−

200

−

5

x

=

40

So, there were 40 tourist class passengers.

Now first class passengers

=

52

−

x

=

52

−

40

=

12

∴

There were 40 tourist class passengers and 12 first class passengers.  

As a check

Total money paid = $25(tourist class)+$30(first class)  

R

H

S

=

$

25

(

40

)

+

$

30

(

12

)

$

1000

+

$

360

=

$

1360

L

H

S

=

$

1360

Hence verified.

8 0
3 years ago
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