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steposvetlana [31]
3 years ago
9

Find the missing factor. Write your answer in exponential form. 9^-6= (?) • 9^-2

Mathematics
1 answer:
jeka943 years ago
7 0

Answer:

9^-4

Step-by-step explanation:

9^-6=?*9^-2

Let the unknown=x

9^-6=x*9^-2

9^-6=9^-2(x)

x=1/9^6÷1/9^2

=1/9^6×9^2/1

=9^2/9^6

x=1/9^4

x=9^-4

Check

9^-4*9^-2

=9^-4-2

=9^-6

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RUDIKE [14]
It is the 3rd answer
6 0
2 years ago
A^2 + b^2 + c^2 = 2(a − b − c) − 3. (1) Calculate the value of 2a − 3b + 4c.
Verdich [7]

Answer:

2a - 3b + 4c = 1

Step-by-step explanation:

Given

a^2 + b^2 + c^2 = 2(a - b - c) - 3

Required

Determine 2a - 3b + 4c

a^2 + b^2 + c^2 = 2(a - b - c) - 3

Open bracket

a^2 + b^2 + c^2 = 2a - 2b - 2c - 3

Equate the equation to 0

a^2 + b^2 + c^2 - 2a + 2b + 2c + 3 = 0

Express 3 as 1 + 1 + 1

a^2 + b^2 + c^2 - 2a + 2b + 2c + 1 + 1 + 1 = 0

Collect like terms

a^2 - 2a + 1 + b^2 + 2b + 1 + c^2  + 2c + 1 = 0

Group each terms

(a^2 - 2a + 1) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

Factorize (starting with the first bracket)

(a^2 - a -a + 1) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

(a(a - 1) -1(a - 1)) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

((a - 1) (a - 1)) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

((a - 1)^2) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

((a - 1)^2) + (b^2 + b+b + 1) + (c^2  + 2c + 1) = 0

((a - 1)^2) + (b(b + 1)+1(b + 1)) + (c^2  + 2c + 1) = 0

((a - 1)^2) + ((b + 1)(b + 1)) + (c^2  + 2c + 1) = 0

((a - 1)^2) + ((b + 1)^2) + (c^2  + 2c + 1) = 0

((a - 1)^2) + ((b + 1)^2) + (c^2  + c+c + 1) = 0

((a - 1)^2) + ((b + 1)^2) + (c(c  + 1)+1(c + 1)) = 0

((a - 1)^2) + ((b + 1)^2) + ((c  + 1)(c + 1)) = 0

((a - 1)^2) + ((b + 1)^2) + ((c  + 1)^2) = 0

Express 0 as 0 + 0 + 0

(a - 1)^2 + (b + 1)^2 + (c  + 1)^2 = 0 + 0+ 0

By comparison

(a - 1)^2 = 0

(b + 1)^2 = 0

(c  + 1)^2 = 0

Solving for (a - 1)^2 = 0

Take square root of both sides

a - 1 = 0

Add 1 to both sides

a - 1 + 1 = 0 + 1

a = 1

Solving for (b + 1)^2 = 0

Take square root of both sides

b + 1 = 0

Subtract 1 from both sides

b + 1 - 1 = 0 - 1

b = -1

Solving for (c  + 1)^2 = 0

Take square root of both sides

c + 1 = 0

Subtract 1 from both sides

c + 1 - 1 = 0 - 1

c = -1

Substitute the values of a, b and c in 2a - 3b + 4c

2a - 3b + 4c = 2(1) - 3(-1) + 4(-1)

2a - 3b + 4c = 2 +3  -4

2a - 3b + 4c = 1

7 0
3 years ago
(15 POINTS) (FOLLOW DIRECTIONS ON ATTACHMENT!)
zmey [24]

Answer:

1. 5 / 6

2. 1 / 3

3. 3 / 6 or  1 / 2

Step-by-step explanation:

The probability that A is not yellow is 5 / 6

The probability that B is blue is 1 / 3

The probability that A is red is 3 / 6 or 1 / 2

6 0
3 years ago
Help me with this question please!!
mariarad [96]
It should be answer B
7 0
3 years ago
( 2, 2)<br> ( 0, 3)<br> ( 1, 5)<br> (6, 7)<br> (4, 8)<br> (7, 0)
Lesechka [4]
L = (2,2)

H = (0,3)

G = (1,5)

M = (6,7)

P = (4,8)

C = (7,0)


8 0
3 years ago
Read 2 more answers
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