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Norma-Jean [14]
4 years ago
13

What is thirty-seven and nine tenths writtenbin expanded form?

Mathematics
2 answers:
AlexFokin [52]4 years ago
6 0
3x10 + 7x1 + 9x 1/10  and that could possibly be wrong
gulaghasi [49]4 years ago
3 0
37 and 9/10
37 9/10
Hope this helped.
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Consider the transpose of Your matrix A, that is, the matrix whose first column is the first row of A, the second column is the
Zarrin [17]

Answer:The system could have no solution or n number of solution where n is the number of unknown in the n linear equations.

Step-by-step explanation:

To determine if solution exist or not, you test the equation for consistency.

A system is said to be consistent if the rank of a matrix (say B ) is equal to the rank of the matrix formed by adding the constant terms(in this case the zeros) as a third column to the matrix B.

Consider the following scenarios:

(1) For example:Given the matrix A=\left[\begin{array}{ccc}1&2\\3&4\end{array}\right], to transpose A, exchange rows with columns i.e take first column as first row and second column as second row as follows:

Let A transpose be B.

∵B=\left[\begin{array}{ccc}1&3\\2&4\end{array}\right]

the system Bx=0 can be represented in matrix form as:

\left[\begin{array}{ccc}1&3\\2&4\end{array}\right]\left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right]=\left[\begin{array}{ccc}0\\0\end{array}\right] ................................eq(1)

Now, to determine the rank of B, we work the determinant of the maximum sub-square matrix of B. In this case, B is a 2 x 2 matrix, therefore, the maximum sub-square matrix of B is itself B. Hence,

|B|=(1*4)-(3*2)= 4-6 = -2 i.e, B is a non-singular matrix with rank of order (-2).

Again, adding the constant terms of equation 1(in this case zeros) as a third column to B, we have B_{0}:      

B_{0}=\left[\begin{array}{ccc}1&3&0\\4&2&0\end{array}\right]. The rank of B_{0} can be found by using the second column and third column pair as follows:

|B_{0}|=(3*0)-(0*2)=0 i.e, B_{0} is a singular matrix with rank of order 1.

Note: a matrix is singular if its determinant is = 0 and non-singular if it is \neq0.

Comparing the rank of both B and B_{0}, it is obvious that

Rank of B\neqRank of B_{0} since (-2)<1.

Therefore, we can conclude that equation(1) is <em>inconsistent and thus has no solution.     </em>

(2) If B=\left[\begin{array}{ccc}-4&5\\-8&10&\end{array}\right] is the transpose of matrix A=\left[\begin{array}{ccc}-4&-8\\5&10\end{array}\right], then

Then the equation Bx=0 is represented as:

\left[\begin{array}{ccc}-4&5\\-8&10&\end{array}\right]\left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right]=\left[\begin{array}{ccc}0\\0\end{array}\right]..................................eq(2)

|B|= (-4*10)-(5*(-8))= -40+40 = 0  i.e B has a rank of order 1.

B_{0}=\left[\begin{array}{ccc}-4&5&0\\-8&10&0\end{array}\right],

|B_{0}|=(5*0)-(0*10)=0-0=0   i.e B_{0} has a rank of order 1.

we can therefor conclude that since

rank B=rank B_{0}=1,  equation(2) is <em>consistent</em> and has 2 solutions for the 2 unknown (X_{1} and X_{2}).

<u>Summary:</u>

  • Given an equation Bx=0, transform the set of linear equations into matrix form as shown in equations(1 and 2).
  • Determine the rank of both the coefficients matrix B and B_{0} which is formed by adding a column with the constant elements of the equation to the coefficient matrix.
  • If the rank of both matrix is same, then the equation is consistent and there exists n number of solutions(n is based on the number of unknown) but if they are not equal, then the equation is not consistent and there is no number of solution.
5 0
3 years ago
(x+3)^2 and x^2+9 is equivalent?
chubhunter [2.5K]
They are not equivalent, try adding in numerical values for x, both do not come out the same.
3 0
4 years ago
ALL MY POINTS PLZ BE RIGHT
shepuryov [24]

Answer:

-xy^6 +2y -6

Step-by-step explanation:

(-6x^2 y^8+12xy^3-36xy^2)

-------------------------------------------

6xy^2

Divide each term by 6 in the numerator and denominator

(-6/6x^2 y^8+12/6xy^3-36/6xy^2)

-------------------------------------------

6/6xy^2

-x^2y^8 +2xy^3 -6xy^2

---------------------------------

xy^2

Divide each term by x in the numerator and denominator

-x^2/xy^8 +2x/xy^3 -6x/xy^2

---------------------------------

x/xy^2

-xy^8 +2y^3 -6y^2

---------------------------------

y^2

Divide each term by y^2 in the numerator and denominator

Remember when dividing, we subtract the exponents

-xy^8/y^2 +2y^3/y^2 -6y^2/y^2

---------------------------------

y^2 /y^2

-xy^6 +2y^1 -6

---------------------------------

1

-xy^6 +2y -6

7 0
3 years ago
Read 2 more answers
Ms. Hamby gave a quiz. Two students' work and the answer key are shown. Ms. Hamby accepts equivalent answers in any form. Part A
Zina [86]

Answer:

attach a picture

Step-by-step explanation:

4 0
3 years ago
Use the graph to find the
Dmitry [639]
The y intercept is 2, because that is the value of y when it crosses the y axis.

Since the line is pointing down, it has a negative slope, and since the y value goes down 2 for every 3 x values, the slope is -2/3. You should always right the slope in rise/run form, or change in y/change in x.

Finally, write the equation in the form of y=mx+b, where m is the slope and b is the y intercept. This means the equation of the line is y=-2/3x+2.
7 0
2 years ago
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