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Inessa05 [86]
3 years ago
7

Pls answer it......​

Mathematics
1 answer:
KatRina [158]3 years ago
7 0

Answer: The cost price for Hari is 840 RS,

The cost price for Ram is 800 Rs

Step-by-step explanation: We start by working back with the profit made by Hari which is given as RS 882. What this means is that after selling the camera Ram has RS 882 which is made up of the cost price plus the profit or we can denote this figure as 105%.

To compute the extra 5% on 882, we can write out the following expression

882/x = 105/100

Where 882 is the cost price plus the 5% profit and x is the cost price. Hence 882/x = 105/100

By cross multiplication we now have

882 × 100 = 105x

88200 = 105x

Divide both sides of the equation by 105

840 = x

The cost price for Hari is Rs 840. That means Ram sold it at RS 840 and made a 5% profit. We shall adopt a similar approach to calculate Ram's cost price, which is

840/y = 105/100

Where 840 is the cost price plus the 5% profit and y is the cost price

Hence 840/y = 105/100

By cross multiplication we now have

840 × 100 = 105y

84000 = 105y

Divide both sides of the equation by 105

800 = y

The cost price for Ram is Rs 800.

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I’m stuck, please give the explanation for the first question.
gladu [14]
----------------------------------------------
Define x:
----------------------------------------------
Let x be the number of students in the second class:
⇒second class = x

There are 3 more students in the first class than in the second class:
⇒first class = x + 3

There are 2 more students in the third class than in the second class:
⇒third class = x + 2

----------------------------------------------
Expression for each class:
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First class = x + 3
Second class = x
Third class = x + 2

----------------------------------------------
Expression for total number of students:
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Total = x + 3 + x + x + 2
Total =  3x + 5

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Find x:
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----------------------------------------------
Find the number of students in each class:
----------------------------------------------
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--------------------------------------------------------------------------------------------
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4 years ago
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Records on a fleet of trucks reveal that the average life of a set of spark plugs is normally distributed with a mean of 22,100
fgiga [73]

Answer:

There no sufficient evidence to support the manufactures claim at the 0.05 level

Step-by-step explanation:

From the question we are told that

   The  mean is  \mu  =  22100 \ miles

    The  sample mean is \= x  =  23400 \ miles

   The  sample size is  n  = 18

   The standard deviation is \sigma  =  1 500 miles

    The test statistics is  t = 3.677

    The level of significance is \alpha  =  0.05

The null hypothesis  is  H_o :  \mu =  22100

The  alternative hypothesis  is  H_a :  \mu  \ne 22100

Generally the p-value  is mathematically represented as

     p-value  =  2 *  P(t >3.677 )

From the z-table  P(t >3.677 )  =  0.000118

So

    p-value  =  2 *  0.000118

=> p-value  =  0.000236

From he value given and obtained we see that  p-value  <  \alpha

Hence we reject the null hypothesis

Hence there no sufficient evidence to support the manufactures claim

8 0
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