What are the roots of the polynomial equation x^3-6x=3x^2-8? Use a graphing calculator and a system of equations.
2 answers:
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Answer:
A
Step-by-step explanation:
Using the definition
n =
where n! = n(n - 1)(n - 2).... × 3 × 2 × 1
Then evaluating numerator and denominator
10
=
=
Cancel 7(6)(5)(4)(3)(2)(1) on numerator/ denominator, leaving
= =
= 120
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6
=
=
Cancel 4(3)(2)(1) on numerator/ denominator, leaving
=
= 15
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Dividing numerator by denominator gives
= 8 → A