All categories

4 years ago

Which statement is true about the function f(x)= StartRoot negative x EndRoot?

Mathematics

2 answers:

tia_tia [17]4 years ago

8 0

Answer:

the answer is - The range of the function is all real numbers greater than or equal to 0.

Step-by-step explanation:

UNO [17]4 years ago

4 0

Answer:

The domain of the graph is all real numbers less than or equal to 0

Step-by-step explanation:

we have the function

$f(x)=\sqrt{-x}$

we know that

The radicand must be positive

$-x \geq 0$

Solve for x

Multiply by -1 both sides

$x\leq 0$

The domain is the interval ------> (-∞,0]

All real numbers less than or equal to zero

The range of the function is the interval -----> [0,∞)

$f(x)\geq 0$

see the attached figure to better understand the problem

All real numbers greater than or equal to zero

Verify each statement

case 1) The domain of the graph is all real numbers

The statement is false

Because, the domain is all real numbers less than or equal to zero

case 2) The range of the graph is all real numbers

The statement is false

Because, the range is all real numbers greater than or equal to zero

case 3) The domain of the graph is all real numbers less than or equal to 0

The statement is true

case 4) The range of the graph is all real numbers less than or equal to 0

The statement is false

Because, the range is all real numbers greater than or equal to zero

You might be interested in

Express the function as the sum of a power series by first using partial fractions. f(x) = 8 x2 − 4x − 12 f(x) = ∞ n = 0 find th

alexandr1967 [171]

I'm guessing the function is

$f(x)=\dfrac8{x^2-4x-12}=\dfrac8{(x-6)(x+2)}$

which, split into partial fractions, is equivalent to

$\dfrac1{x-6}-\dfrac1{x+2}$

Recall that for $|x|$ we have

$\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n$

With some rearranging, we find

$\dfrac1{x-6}=-\dfrac16\dfrac1{1-\frac x6}=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n$

valid for $\left|\dfrac x6\right|$ , or $|x|$ , and

$\dfrac1{x+2}=\dfrac12\dfrac1{1-\left(-\frac x2\right)}=\displaystyle\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

valid for $\left|-\dfrac x2\right|$ , or $|x|$ .

So we have

$f(x)=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n-\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

$f(x)=\displaystyle-\sum_{n=0}^\infty\left(\frac{x^n}{6^{n+1}}+\frac{(-x)^n}{2^{n+1}}\right)$

$f(x)=\displaystyle-\sum_{n=0}^\infty\frac{1+3(-3)^n}{6^{n+1}}x^n$

Taken together, the power series for $f(x)$ can only converge for $|x|$ , or $-2$ .

6 0

3 years ago

9.05 as a improper fraction

Norma-Jean [14]

Answer:

181/20

Step-by-step explanation:

3 0

3 years ago

ABC ~ ADE; find x Pls help!!

Lubov Fominskaja [6]

Step-by-step explanation:

If ABC~ADE
then DE~BC

$\sf \rightarrowtail \: 2x + 3 = 15 \\ \sf \rightarrowtail \: 2x = 15 - 3 \\ \sf \rightarrowtail \: 2x = 12 \\ \sf \rightarrowtail \: x = \frac{12}{2} \\ \sf \rightarrowtail \: x = 6$

8 0

3 years ago

Match the statement to symbols a quarter of a number 4/x 4x ox/4 1/4+x

Reil [10]

A quarter of the number would be 1/4 +x

7 0

3 years ago

Geraldo was a counselor at summer camp. He needed to divide the 40 children into 4 teams, so he put 10 red, 10 blue, 10 yellow,

viva [34]

The probability that the first 3 children will all draw a blue marble is 10 out of 40 .

3 0

3 years ago