Using the discrete probability outputs given in the attached table ; the probability values of having exactly 6 ; and having 6 or more girls are :
<u>The </u><u>probability</u><u> of having </u><u>exactly 6 girls</u><u> can be defined as</u> :
- P(X = 6) = 0.111 (from the discrete probability table)
2.)
<u>The </u><u>probability</u><u> of having </u><u>6 or more</u><u> girls can be defined as</u> :
- P(X ≥ 6) = P(X = 6) + P(X = 7) + P(X = 8)
- From the table attached :
- P(X ≥ 6) = 0.111 + 0.014 + 0.003 = 0.1
Therefore, the probability of having exactly 6 girls is 0.111 while the probability of having 6 or more girls is 0.1
Learn more : brainly.com/question/18153040
DOMAIN: [0, +6)
RANGE: (-2.5, +2.5)
REMEMBER THAT THE DOMAIN IS SET ACCORDING TO THE GRAPH’S RELATION TO THE X-AXIS (-X, +X).
REMEMBER THAT THE RANGE IS ISET ACCORDING TO THE GRAPH’S REALTION TO THE Y-AXIS (-Y, +Y).
REMEMBER THAT THE BEST WAY TO APPRECIATE THIS AID TO YOUR LEARNING TO MARK “BRAINLIEST”.
Answer:
Graph A.
Step-by-step explanation:
The graph has a local minimum around x=-2 since it slightly curves downwards around this region. Moreover, the graph of the rational function has a horizontal asymptote at y=1 since the graph approaches this horizontal line but never touches nor crosses it
Answer:
$8.50
Step-by-step explanation:
I don't know what Alls are, but if Carlos insists, we can calculate how much he can spend on Alls with the expression:
($31.50) + r 
$40
This says the sum of what Carlos has already spent (hot dogs and hamburgers) plus the amount he spends on Alls (rolls?), r, must be equal to or less than the $40 he has allowed himself to spend.
($31.50) + r $40
r $40 - $31.50
r $8.50
