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olga55 [171]
3 years ago
5

A company is experiencing overwhelming visits to a main web server. The IT department is developing a plan to add a couple more

web servers for load balancing and redundancy. Which requirement of information security is addressed by implementing the plan?
(A) integrity
(B) scalability
(C) availability
(D) confidentiality
Computers and Technology
2 answers:
Varvara68 [4.7K]3 years ago
5 0
The answer is C) Availability.

Although the company is addressing scalability by adding more servers, the question is asking for security requirement. Therefore we need to choose one of the principles from CIA triad which includes confidentiality, integrity, and availability.

Integrity involves keeping the data accurate and confidentiality involves keeping the data between the sender and intended recipient(s). That being said, scalability and availability are the possible answers.

C) Availability is the best answer because it is part of the CIA triad.

Note: Another resource to look at for cyber security principles would be the Parkerian Hexad.
Gnoma [55]3 years ago
3 0

Explanation:

The three goals of information security are:

- integrity

- availability

- confidentiality

Since adding additional servers help relieve overloading by load balancing and redundancy, it will address availability AND integrity.

However, the major issue at hand is solving the overwhelming visits to the server, the plan address the aspect of availability.

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Answer:

2.342m

Explanation:

Given

Time = 0.5 s

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Because the pot was in view for a total of 0.5 seconds, we can assume that it took the cat 0.25 seconds to go from the bottom of the window to the top

Using this equation of motion

S = ut - ½gt²

Where s = 2

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t = 0.25

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So, we have.

2 = u * 0.25 - ½ * 9.8 * 0.25²

2 = 0.25u - 0.30625

2 + 0.30625 = 0.25u

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u = 2.30625/0.25

u = 9.225 m/s ------------ the speed at the bottom of the pot

Using

v² = u² + 2gs to calculate the height above the window

Where v = final velocity = 0

u = 9.225

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So, we have

0² = 9.225² - 2 * 9.8 * s

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Then 4.342 - 2 is the distance above the window

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