Answer:
Step-by-step explanation: One important property of a square is that all the sides of the square have the same length. That means, if a square has a perimeter of P, then one side must have a length of P/4 units. So for a square with a perimeter of (12x + 52) units, its sides would have a length of (12x + 52)/4 = (3x + 13) units. Therefore, the answer is C: (3x + 13) units.
Answer:
where is the chart?
Step-by-step explanation:
Answer:
∠AKB = 22°
Step-by-step explanation:
Call the point of intersection of BK and AC point P. Then line BK is a transversal to parallel lines AK and BC. Alternate interior angles AKB and PBC will be congruent.
We know that angle PCB is 68°, the difference between 180° and the sum of the two given angles in ΔABC:
∠PCB = 180° -∠PAB -∠ABC = 180° -59° -53° = 68°
Since PB is an altitude, ∠CPB is a right angle. Then ∠PBC is the complement of ∠PCB, so is ...
∠PBC = 90° -68° = 22°
As we said, this is congruent to ∠AKB, so ...
∠AKB = 22°
Answer:
Option a is right
the probability that we would see a test statistic this extreme or more if the null hypothesis were true.
Step-by-step explanation:
In hypothesis testing we fix null and alternate hypothesis. The conclusion of the test depends on the p value of the test.
The p value also known as probability value is the estimated probability of rejecting the null hypothesis when it is actually true.
It can be said the extreme value i.e. if p value is atleast this much we accept null hypothesis.
Hence out of the options given correct choice is
the probability that we would see a test statistic this extreme or more if the null hypothesis were true.
Answer:
The price of
1 adult ticket = $15
1 student ticket = $9
Step-by-step explanation:
Let
The price of adult tickets be represented by a
The price of student tickets be represented by s
Therefore:
On the first day of ticket sales the school sold 4 adult tickets and 10 student tickets for a total of $150.
4a + 10s = $150.... Equation 1
The school took in $105 on the second day by selling 1 adult ticket and 10 student tickets.
a + 10s = $105.... Equation 2
a = $105 - 10s
Therefore, we substitute : $105 - 10s = a in Equation 1
4a + 10s = $150.... Equation 1
4($105 - 10s) + 10s = $150
$420 - 40s + 10s = $150
Collect like terms
- 40s + 10s = $150 - $420
-30s = -$270
Divide both sides by -30
-30s/-30 = -$270/-30
s = $9
We find a
a = $105 - 10s
a = $105 - 10($9)
a = $105 - $90
a = $15
Therefore, the price of
1 adult ticket = $15
1 student ticket = $9
