What is the lowest possible common multiple of 2 distinct integers, each greater than 251?
1 answer:
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Answer:
x =
Step-by-step explanation:
Using the Altitude- on- Hypotenuse theorem
(leg of Δ ABC )² = (part of hypotenuse below it ) × ( whole hypotenuse )
x² = 3 × (3 + 7) = 3 × 10 = 30 ( take the square root of both sides )
x =
