(tan(<em>x</em>) + cot(<em>x</em>)) / (tan(<em>x</em>) - cot(<em>x</em>)) = (tan²(<em>x</em>) + 1) / (tan²(<em>x</em>) - 1)
… = (sin²(<em>x</em>) + cos²(<em>x</em>)) / (sin²(<em>x</em>) - cos²(<em>x</em>))
… = -1/cos(2<em>x</em>)
Then as <em>x</em> approaches <em>π</em>/2, the limit is -1/cos(2•<em>π</em>/2) = -sec(<em>π</em>) = 1.
Answer:
m∠ TRS = 60° , m∠ SRW = 120°
Step-by-step explanation:
First, find x
∠TRS = ∠VRW (vertically opposite angles are equal)
x + 40° = 3x
x - 3x = -40
-2x = -40
x = -40/-2
x = 20
m∠ TRS = 60° [x + 40 = 20+40 = 60]
m∠ SRW + m∠ TRS = 180° (linear pair)
m∠ SRW + 60° = 180°
m∠ SRW = 180° - 60°
m∠ SRW = 120°
hope this helps you
Answer:
area=108
Step-by-step explanation:
length times width
8x6=48
10x4=40
5x4=20
---------
Add them all together 48+40+20 =108
Answer:
Step-by-step explanation:
5 = 6y
y =
Answer:
This is a protractor question if you dont have one then try these on a calculator.
when angle is between two lines we need see where the hypotenuse is in the diagram and where is the adjacent.
And whether the triangle is right angle or not.
Try these
shift sin -1 x sin 9/6 (for opp/hyp)
shift sin -1 (9/6) (for opp/hyp)
shift sin -1 x sin 6/9 (for opp/hyp)
shift sin -1 (6/9) (for opp/hyp)
shift cos -1 x cos 9/6 (for adj/hyp)
shift cos -1 (9/6) (for adj/hyp)
shift cos -1 x cos (6/9) (for adj/hyp)
shift cos -1 (6/9) (for adj/hyp)
shift tan -1 x tan (9/6) ( for opp/adj)
and so on....
Step-by-step explanation:
