Answer:
See below.
Step-by-step explanation:
<u>a. If h is the number of hours of labour required to print the cards, construct an equation for the cost of the cards, C.</u>
C = $250 + ($40/hr)*h
<u>b. You have budgeted $1000 for the printing job. How many hours of labour can you afford? Give your answer to the nearest minute.</u>
$1000 = $250 + ($40/hr)*h
($40/hr)*h = $750
h = 18.75 hours
(18.75 hours)(60 min/hr) = 1125 minutes
<u>c. The company estimates that it can print 1000 cards per hour of labour. How many cards will you get printed with your current budget?</u>
(18.75 hr)*(1000 cards/hr) = 18,750 cards
<u>d. An alternative to printing is photocopying. The company charges 15 cents per side for the first 10 000 cards and then 10 cents per side for the remaining cards. Which is the cheaper option for 18 750 single-sided cards and by how much?</u>
Photocopy Cost for the first 1000 single-sided cards is:
(1000 cards)*($0.15) = $150
Photocopy Cost for the final 17,750 single-sided cards is:
(17,750)*($0.10) = $1,775
Totoal photocopy cost for 18,750 single-sided cards is $1,925. [1775+150]
The cheapest option for 18,750 cards is printing: $1,000
Printing is (1,925 - 1000) $925 cheaper than photocopying.
A and B implies, that ABCD is a parallelogram. So, there diagonals AC and BD were intersecting.