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Lina20 [59]
3 years ago
15

A total of 6.825 inches of snow fell during a storm the snow fell at an average rate of 1.3 inches per hour for how many hours d

id the snow fall
Mathematics
1 answer:
ziro4ka [17]3 years ago
8 0
If the snow falls at a rate of 1.3 inches per hour, dividing 6.825 into 1.3 should give you your answer.
6.825/1.3 = 5.25
Therefore, the snow was falling for 5.25 hours, or 5 hours and 15 minutes.
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Aleks04 [339]

Answer:

im gonna say 4 if im wrong its my fault

8 0
3 years ago
the sum of two consecutive integers is -49 write an equation that models this situation and find the values of the two integers
hodyreva [135]
Х is the first <span>integer
</span>(x+1) is the second integer

x + x + 1 = -49
2x + 1 = - 49
2x = -49 - 1
2x = -50
x = -25  first integer
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Answer: -25 and -24
7 0
3 years ago
Read 2 more answers
14k=84 solve the equation and check your solution ​
UNO [17]

Answer:

k = 6

Step-by-step explanation:

14k=84

k = 84/14

k = 6

to check the equation:

14k ..we found that k is 6, so replace k with 6

14(6)

84 ......checked.

5 0
2 years ago
The prior probabilities for events A1 and A2 are P(A1) = 0.35 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(
forsale [732]

Answer:

Step-by-step explanation:

Hello!

Given the probabilities:

P(A₁)= 0.35

P(A₂)= 0.50

P(A₁∩A₂)= 0

P(BIA₁)= 0.20

P(BIA₂)= 0.05

a)

Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)

Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.

b)

Considering that P(BIA)= \frac{P(AnB)}{P(A)} you can clear the intersection from the formula P(AnB)= P(B/A)*P(A) and apply it for the given events:

P(A_1nB)= P(B/A_1) * P(A_1)= 0.20*0.35= 0.07

P(A_2nB)= P(B/A_2)*P(A_2)= 0.05*0.50= 0.025

c)

The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:

P(B)= (A₁∩B) + P(A₂∩B)=  0.07 + 0.025= 0.095

d)

The Bayes' theorem states that:

P(Ai/B)= \frac{P(B/Ai)*P(A)}{P(B)}

Then:

P(A_1/B)= \frac{P(B/A_1)*P(A_1)}{P(B)}= \frac{0.20*0.35}{0.095}= 0.737 = 0.74

P(A_2/B)= \frac{P(B/A_2)*P(A_2)}{P(B)} = \frac{0.05*0.50}{0.095} = 0.26

I hope it helps!

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3 years ago
The coordinates of the vertices of triangle QRS are Q (1,-2), R (1,9),
Darina [25.2K]

I think 1700000000000000000

5 0
2 years ago
Read 2 more answers
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