Answer:
See Below.
Step-by-step explanation:
We are given that ΔAPB and ΔAQC are equilateral triangles.
And we want to prove that PC = BQ.
Since ΔAPB and ΔAQC are equilateral triangles, this means that:
Likewise:
Since they all measure 60°.
Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:
Likewise:
Since ∠QAC ≅ ∠PAB:
And by substitution:
Thus:
Then by SAS Congruence:
And by CPCTC:
Answer:
=> Apply law of cosine
=> input value
=> simplify
=> calulcation
=> apply rule: Distance must be greater than 0
which is about 14.51828
Answer:
Okay buddy the answer is 63 because if you look at all the angles they are suppose to add up to 180 so with the line D and A the angles is 128 so the angle on the other side is 52 so 52 plus65 is 117 so then 180-117 is 63
Step-by-step explanation:
mark me branliest
I do not completely understand your question, but if you mean area by "murals", then when the width increases, area does, too. For example:
I have a rectangular board that is 5 feet by 3 feet. The area is 15 square feet. I have another board with a longer width, but the same length. It is 5 feet by 4 feet. Its area is 20 square feet.
Answer:
first bring x value together
Step-by-step explanation:
like 2x and 3x together and then take 5/3 to RHS and solve
