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3 years ago

Which of the following equations represents the greatest value of x?

1 answer:

Nutka1998 [239]3 years ago

7 0

Solve for x to determine which equation represents the greatest value for x.

Equation 1

$x^2 = 17$

$x$ ≈ $4.12$

Equation 2

$x^2 = 26$

$x$ ≈ $5.1$

Equation 3

$x^3 = 64$

$x=4$

Equation 4

$x^3 = 27$

$x=3$

Answer: Equation 2

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If 3m = 12, what is the value of 6(m - 1)?

Bezzdna [24]

12/3=4
so m=4

6x4=24
6x1=6

24-6=18

7 0

3 years ago

Read 2 more answers

Write the equation of a line in the given form.

Gnom [1K]

Answer:

$y = \frac{1}{4}x - 5$

Step-by-step explanation:

Slope intercept form: y = mx + b

Find slope:

m = (y₂ - y₁) / (x₂ - x₁)

= (-5 - (-4)) / (0 - 4)

= -1 / -4

= 1/4

Find y intercept using anyone of the given points and slope from above:

y = mx + b

$-5 = \frac{1}{4}(0) + b$

b = -5

Now use the above slope and y intercept to create equation of a line:

$y = \frac{1}{4}x - 5$

3 0

3 years ago

Can u guys help pls?

Contact [7]

Answer:

$(2 {n}^{2} ) ^{4} \\ 2 \times 2 \times 2 \times 2 \times {n}^{2 \times 4} \\ {2}^{4} \times {n}^{8} \\ = 16 {n}^{8}$

<h3>Answer B is correct</h3>

7 0

4 years ago

Jake has a rectangular garden that measures 12 feet by 14 feet. He wants to increase the area by 50% and plans to increase each

emmasim [6.3K]

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

$x\approx 2.9ft$

<h2>Explanation:</h2><h2 />

First of all, let's calculate the area of the original rectangular garden:

$A=b\times h \\ \\ b:base \\ \\ h:height \\ \\ \\ b=12ft \\ \\ h=14ft \\ \\ \\ A=12(14) \\ \\ A=168ft^2$

Jake wants to increase the area by 50%, so the new area would be:

$A'=168(1.5) \\ \\ A'=252ft^2$

He wants to increase the area by 50% and plans to increase each dimension by equal lengths, x, so this is represented by the figure below, therefore:

$(12+x)(14+x)=252 \\ \\ 168+12x+14x+x^2-252=0 \\ \\ x^2+26x-84=0 \\ \\ \\ Using \ quadratic \ formula: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ \\ b=26 \\ \\ c=-84 \\ \\ \\ x=\frac{-26 \pm \sqrt{26^2-4(1)(-84)}}{2(1)} \\ \\ x=\frac{-26 \pm \sqrt{1012}}{2} \\ \\ \\ Two \ solutions: \\ \\ x_{1}=-13+\sqrt{253} \approx 2.9\\ \\ x_{2}=-13-\sqrt{253} \approx -28.9 \\ \\ x_{2} \ is \ discarded \ because \ it \ can't \ be \ negatives$

Finally:

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

$x\approx 2.9ft$

<h2>Learn more:</h2>

Dilation: brainly.com/question/10945890

#LearnWithBrainly

6 0

3 years ago

Help<br> Simplify. 2−4÷2+2^3

Radda [10]

Hey there!

If we use pemdas:

P - Parentheses
E - Exponents
M - Multiplicatiom
D - Division
A - Addition
S - Subtractiom

We know we have to evaluate the exponent first. Two to the rid power is equal to 8. Therefore, we have:

2 - 4/2 + 8

Next, we do the division. -4/2 = -2, so we have:

2-2 + 8 = 0 + 8 = 8

Hope this helps!

3 0

4 years ago

Read 2 more answers