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enyata [817]
3 years ago
13

Timothy drove his race car 10% farther using the gasoline from Smith's Station compared to gasoline from Jack's Station. After T

imothy filled his gas tank at Jack's Station, he traveled 480 miles. How far did he travel on a tank of gas from Smith's Station?
Mathematics
1 answer:
Fiesta28 [93]3 years ago
5 0

Answer:

528

Step-by-step explanation:

x = 480

1.1 x = 480 * 1.1

480 + 48 = 528

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A right angle intersects a line at point M.Which statement is true about angles 1 and 2They are congruent.
SOVA2 [1]

Answer:

they are complementary

Step-by-step explanation:

4 0
3 years ago
Tell whether the angles are vertical or adjacent and solve for x. Solve 11 and 12 for 20 points and brainest.
stiv31 [10]

Answer:

11) x = 45

12) x = 30

Step-by-step explanation:

11)

3x + x = 180

4x = 180

x = 45

12)

4x = 5x - 30

4x - 5x = -30

-x = -30

x = 30

5 0
3 years ago
(2p + 4) + 5 (p-1) - (p+7)
svetoff [14.1K]

<em>Your answer will be, </em><em>"6p - 8"</em>

Thanks,

<em>Deku ❤</em>

4 0
2 years ago
Read 2 more answers
2 points) Suppose w=xy+yzw=xy+yz, where x=et, y=2+sin(t)x=et, y=2+sin⁡(t), and z=2+cos(3t)z=2+cos⁡(3t). A ) Use the chain rule t
Olenka [21]

Answer:

\frac{\partial w}{\partial t}  = y(e^t) +(x+z)*(cos(t))  - 3y*sin(3t)

Step-by-step explanation:

First, note that

\frac{\partial x}{\partial t}  = e^{t} \\\frac{\partial y}{\partial t}  = cos(t)\\

And using the chain rule in one variable

\frac{\partial z}{\partial t}  = -3sin(3t)

Now remember that the chain rule in several variables sates that

\frac{\partial w}{\partial t}  = \frac{\partial w}{\partial x} * \frac{\partial x}{\partial t} + \frac{\partial w}{\partial y} * \frac{\partial y}{\partial t} + \frac{\partial w}{\partial z} * \frac{\partial z}{\partial t}

Therefore the chain rule in several variables would look like this.

\frac{\partial w}{\partial t}  = y(e^t) +(x+z)*(cos(t))  - 3y*sin(3t)

6 0
3 years ago
Read 2 more answers
If i have a forest composed of 25 species of trees, each with a known abundances, how many events are there in the sample space
Vsevolod [243]
There are 25 species of trees, each with a known abundances. The question is how many possible ways to randomly select one tree there are.
We should calculate the number of combinations. Combinations, because we select item/s from a collection. In this case, when we select only one item, the combination is also a permutation. From set of n objects we select r. In our case: n=25, r=1. 
The equation is: n!/r!(n-r)!= 25!/1!*24!=25*24!/24!=25
There are 25 different outcomes (events).
3 0
3 years ago
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