The points that are 4 units apart are B and D
<h3>Complete question</h3>
Which points are 4 units apart? On a coordinate plane, point A is at (-2, 4), point B is at (3, -6), point C is at (-1, 0), point D is at (3, -2).
B and C
C and D
A and C
B and D
<h3>How to determine the points?</h3>
To do this, we simply calculate the distance using the following equation

Using the given points, we have:




Hence, the points that are 4 units apart are B and D
Read more about distance at:brainly.com/question/15821277
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25,200 hours
112x12=1,344
212x112=23,744
1,344+23,744+112=25,200
Answer:
2nd graph (in the attached pics)
Step-by-step explanation:
Graphically, the <em>x-intercepts of the graph of a quadratic function are its zeroes. </em>
There can be
- no zeroes (where graph doesn't cut the x-axis at all),
- 1 zero (where graph touches the x-axis at one point only), and
- 2 zeros (where the graph cuts the x-axis at 2 points)
Looking at the figures, the 2nd graph has no real zeroes, <em>because the graph doesn't cut the x-axis at all!</em>
<em />
So, the answer is the second graph.
I suppose that when you write "log^6" , you want to say log₆
Change of base formula:
loga b=logc b / logc a
log₆ 120=ln 120 / ln 6=2.67
Answer: log₆ 120=2.67
Answer:
y=1/5x-31/5 (or y=0.2x-6.2 in decimals)
Step-by-step explanation:
x=5y-8 (original equation)
x+8=5y <u>(Addition Property of Equality)</u>
1/5x+8/5=y <u>(Division Property of Equality, </u><u>slope </u><u>of </u><u><em>original equation </em></u><u>is </u><u>1/5</u><u>)</u>
<u />
y-y1=m(x-x1) <u>(point-slope formula)</u>
y-(-5))=1/5(x-(6)) <u>(plug in the slope that was found earlier and the point given in the question)</u>
y+5=1/5(x-6)
y+5=1/5x-6/5 (Distributive Property of Multiplication) Note: 5 = 25/5
<u>y=1/5x-31/5</u> (Subtraction Property of Equality, and there's your answer)
<u>y=0.2x-6.2</u><em> </em>(This is the same answer, but written with decimals)