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sashaice [31]
4 years ago
7

If a line has a slope of 1/2 and a y-intercept of -6, what is the x-coordinate if the y-coordinate is 4

Mathematics
2 answers:
ivanzaharov [21]4 years ago
7 0

Answer:

X=20. Our x coordinate is 20.

Step-by-step explanation:

Based from the given slope of 1/2 and a y-intercept of -6, our equation of a line is y=x/2 -6. To remove the fraction we can multiply the equation by 2 to get 2y=x-12. Using this substitute the value of y coordinate 4.

2(4)= x-12

8+12 =x

X=20.

sveta [45]4 years ago
4 0

Answer:

20

Step-by-step explanation:

since the line has a slope of 1/2, the x coefficient of the line is 1/2. Since the y intercept is -6, we have the equation of the line

x/2 - 6 = y

Since in this case y = 4, we have

x/2 - 6 = 4

x/2      = 10

x          = 20

So the x coordinate is 20 when the y coordinate is 4.

Hope it helps and if it does, please mark me brainliest...

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\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C

Then, the function f(t) is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'

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Hence C' = 264,034,000

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f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) For t = 2015 you have:

f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7

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