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3 years ago

A circle is centered at the point (-3,2) and passes through the point (1,5). What is the radius of the circle?

Mathematics

1 answer:

Akimi4 [234]3 years ago

8 0

Answer:

Step-by-step explanation:

The radius is a distance on a circle from the center to a point on the circle.

We have both of these points describe here in this definition. Using the distance formula will give us the radius.

$\sqrt{(x \text{ difference })^2+(y \text{ difference})^2$

The difference between 1 and -3 is 1-(-3)=4.

The difference between 5 and 2 is 5-2=3.

$\sqrt{4^2+3^2}$

$\sqrt{16+9}$

$\sqrt{25}$

$5$

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Which statment explains how to round 4,826 to the nearest hundred?

faltersainse [42]

Round to 4,800 because 2 &It;5.

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3 years ago

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find the area of triangle qpm. round the answer to the nearest tenth. a. 5.2 square units b. 6.3 square units c. 6.5 square unit

viva [34]

Pls. see attachment.

We need to solve for the angles of the smaller triangle in order to solve for the angle of the larger triangle which would help us solve the missing measurement of a side.

Given:

51 degrees.

Cut the triangle into two equal sides and it forms a right triangle. All interior angles of a triangle sums up to 180 degrees.

180 – 51 – 90 = 39 degrees

39 degrees * 2 = 78 degrees.

Angle Q is 78 degrees.

In the bigger triangle, 4.3 is the hypotenuse. We need to solve for the measurement of the long leg which is the opposite of the 78 degree angle.

We will use the formula:

Sine theta = opposite / hypotenuse

Sin(78 deg) = opposite / 4.3

Sin(78 deg) * 4.3 = opposite

4.21 = opposite. This is also the height of the triangle.

Area of a triangle = ½ * base * height

A = ½ * 3units * 4.21units

A = 6.315 square units.

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3 years ago

At a recent marathon, spectators lined the street near the starting line to cheer for the runners. The crowd lined up 5 feet dee

masha68 [24]

Answer:

29568 people cheered for the runners at the start of the race

Step-by-step explanation:

From the question, the crowd lined up 5 feet deep on both sides of the street for the first mile.

This lined up crowd could be related to a rectangle that is 1 mile long and 5 feet wide.

First, Convert 1 mile to feet

1 mile = 5280 feet

Hence, the length of the rectangle is 5280 feet and the width is 5 feet.

Now, we will determine how many 5 feet by 5 feet square we can get from the 5280 feet by 5 feet rectangle. To do that, we will divide 5280 feet by 5 feet

5280 feet ÷ 5 feet = 1056

Hence, from the rectangle, we can get 1056 5 feet by 5 feet square.

From the question, you estimate that 14 people can comfortably fit in a square that measures 5 feet by 5 feet,

∴ 14 × 1056 people will comfortably fit in the crowed lined up 5 feet deep on one side of the street for the first mile.

14 × 1056 = 14784 people

This is the amount of people that will comfortably fit in the crowed lined up 5 feet deep on one side of the street for the first mile.

Since the crowd lined up on both sides of the street, then

2 × 14784 people will comfortably fit in the crowed lined up 5 feet deep on both sides of the street for the first mile

2 × 14784 = 29568 people

Hence, 29568 people cheered for the runners at the start of the race.

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3 years ago

What’s 6 divided by 3 plus 1,000,000

Marizza181 [45]

Answer:

1000002

Step-by-step explanation:

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3 years ago

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Use the elimination to solve this equation. <br><br> 2x+3y=55 <br> 9x+4y=105

seropon [69]

X=5 y=15 (5,15).
This is how you do it:
-4(2x+3y=55): -8x-12y=-220
3(9x+4y=105):27x+12y=315

You add the two new equations together, canceling out the y values, and get the x value. Then, you go back and plug in the x value in the original equation to get the y value.

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3 years ago