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3 years ago

Estimate by first rounding each number to the nearest integer.

Mathematics

1 answer:

posledela3 years ago

5 0

$4 \frac{1}{9} + 2\frac{ 2}{13} =4 \frac{13}{117} + 2\frac{ 18}{117} =6\frac{31}{117}\approx 6\\ \\Answer: \ \ C.\ \ 6$

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LaToya had a large collection of basketball cards. She decided to give half of them to her friends, Aaron, and a fourth of them

Savatey [412]

1-1/2-1/4=1/4 If 75 is 1/4, then just divide to get the whole thing. 75/1/4=200
She had two hundred cards to start with. Hope this helps!!!

5 0

3 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

Comprei uma bola futebol por R$16,00 e uma bola de basquete por R $9,00. Qual é o preço médio dessas duas bolas?

sukhopar [10]

O preço médio é de R$12,50.

7 0

3 years ago

Find the area of the regular 18-gon with radius 10 mm

777dan777 [17]

Answer:

Step-by-step explanation:

Find the area of the regular 18-gon with radius 10 mm

3 0

3 years ago

Paul and Jim work at a t-shirt factory. They pack t-shirts in boxes and send them

Gwar [14]

Answer:

Jim's box hold more t-shirts by 3 cubic feet

Step-by-step explanation:

Jim's box length = 2 feet

Jim's box breadth = 4 feet

Jim's box height = 6 feet

Volume of box = $Length \times Breadth \times Height = 2 \times 4 \times 6 = 48 feet^3$

Paul's box length = 3 feet

Paul's box breadth =5 feet

Paul's box height = 3 feet

Volume of box = $Length \times Breadth \times Height =3 \times 5 \times 3 = 45 feet^3$

So,Jim's box hold more t shirts by (48-45 = 3 cubic feet )

So, Option C is true

Jim's box hold more t-shirts by 3 cubic feet

3 0

3 years ago