Estimate by first rounding each number to the nearest integer.

Mathematics

1 answer:

posledela3 years ago

5 0

$4 \frac{1}{9} + 2\frac{ 2}{13} =4 \frac{13}{117} + 2\frac{ 18}{117} =6\frac{31}{117}\approx 6\\ \\Answer: \ \ C.\ \ 6$

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I don’t know how to do it

seraphim [82]

The answer to the question is b. 51 megabytes

8 0

3 years ago

Read 2 more answers

Indicate whether the lines are parallel, perpendicular, or neither. Justify your answer.

sveticcg [70]

Note that when two lines have slopes of m₁ and m₂, then
(i) If m₁ = m₂, then the lines are parallel.
(ii) If m₁*m₂ = -1, then the lines are perpendicular.

Let us evaluate the given lines.
a. y = 4x - 1 and 12x = 3y + 7
y = 4x - 1 => m₁ = 4
Write the second equation in standard form.
3y = 12x - 7
y = 4x - 7/3 => m₂ = 4.
m₁ = m₂.
Answer: PARALLEL

b. x - 7y = 10 and 2x + 14y = 21
In standard form,
7y = x - 10 or y = (1/7)x - 10/7 => m₁ = 1/7
14y = - 2x + 21 or y = -1/7 + 3/2 => m₂ = -1/7
m₁ ≠ m₂ and m₁*m₂ ≠ -1.
Answer: NEITHER

c. 5x + 6y = 18 and 18x - 15y = 36
In standard form,
6y = -5x + 18 or y = -(5/6)x + 3 => m₁ = -5/6
15y = 18x - 36 or y = (6/5)x - 12/5 => m₂ = 6/5
m₁*m₂ = -1
Answer: PERPENDICULAR

d. x =1 and y = 1
x = 1 => m₁ is undefined
y = 1 => m₂ = 0
m₁ ≠ m₂ and m₁*m₂ ≠ -1
Answer: NEITHER

6 0

4 years ago

Help please please please please please<br> 6th & 7th

raketka [301]

First lets start with number six. The only way to solve this is if you determine what "a" and "b" are using the first log they have given to you. $log_a_ba=\frac{1}{3}$

The first variable that I solved for was "a" and $a=e^\frac{in(b)}{2}[tex]{[tex] 0$ }

The same is also true for "b", but when you put both "a" and "b" together the only combination that I have found to work is $a=\frac{1}{2} , b=\frac{1}{4}$

Next you plug these numbers in for "a" and "b" on the second equation to get something that looks like this: $log_\frac{1}{2}_*_\frac{1}{4} (\frac{\sqrt{\frac{1}{2}}}{\sqrt[3]{\frac{1}{4}}} )= -\frac{1}{18}$ and the picture below shows where the answer becomes a negative fraction.

https://www.symbolab.com/solver/logarithms-calculator/%20%5Clog_%7B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%5Cfrac%7B1%7D%7B4%7D%7D%5Cleft(%5Cfrac%7B%5Csqrt%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5Cright)

If you paste that link in your search bar it will give you a even more in depth understanding of how to get this answer

Next is #7, the easier of the two.There are two ways to solve for your answers. According to the graph of this equation there are four possible real solutions. $x=2,-2,\sqrt{2}, and -\sqrt{2}$ . (This does not account for any complex solutions)