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Kamila [148]
3 years ago
8

If x is an acute angle and tan x = 5,

Mathematics
1 answer:
lyudmila [28]3 years ago
4 0
We have that
tan x=5

we know that
tan x =sin x/ cos x
sin x/ cos x=5------> squaring-----> sin² x/cos² x=25
remember that
sin² x+cos² x=1-----> cos² x=1-sin² x
substitute
sin² x/[1-sin² x]=25
sin² x=25-25*sin² x
26*sin² x=25
sin² x=25/26
sin x=5/√26

cos² x=1-(5/√26)²----> 1-(25/26)----> 1/26
cos x=1/√26

the answers are
sin x=5/√26
cos x=1/√26

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What is -3(2 - x) = 9x​
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On a family vacation, Aaron took 1,276 digital photos. His twin sister Ashley took 4 times as many as Aaron. Write and solve an
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Equation : 4(1,276) = p

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Step-by-step explanation:

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<u><em>Answers:</em></u>

a. The domain of f is ]-∞ , ∞[

b. The range of f is [-4 , ∞[

c. f(1) = 5

d. The vales of x for which f(x) is -3 are 7 and 9

e. The points at which the graph crosses the x-axis are (6,0) and (10,0)

f. The point where the graph of f crosses the y-axis is (0,5)

g. The values of x for which f(x) < 0 are ]6 , 10[

h. f(-7) is positive

<u><em>Explanation:</em></u>

<u>Part a:</u>

The domain of the function refers to all the possible x-values that can be used as an input for this function.

Taking a look at the graph, we can see that the graph extends endlessly from both ends of the x-axis. This means that all x-values can be used as a domain for the function. In other words, the domain of the function is all the real numbers.

<u>In interval notation, this is written as:</u>

Domain = ]-∞ , ∞[

<u>Part b:</u>

The range of the function refers to all the possible y-values that can be used as an output for the function.

From the graph, we can note that the function extends endlessly in the direction of the positive y-axis while it stops at a value of -4 in the direction of the negative y-axis.

This means that the range of the function starts from -4 (included) and extends to positive infinity.

<u>In interval notation, this is written as:</u>

R = [-4 , ∞[

<u>Part c: </u>

f(1) means that we are looking for the output (the value of y) for which the input (the value of x) is 1.

From the graph, we start by searching for x=1 (first square edge after the origin) and then move vertically till we intersect the graph.

Doing this, we will find that the value of y at x=1 is 5

<u>Therefore:</u>

f(1) = 5

<u>Part d:</u>

f(x) = -3 means that the output value (the value of the y) for the certain input (value of x) is -3

To get the value of x, we go y=-3 and move horizontally till we intersect the graph.

<u>Doing this, we will find that</u> the value of y is -3 at x = 7 and x = 9

<u>Part e:</u>

The points where the graph crosses the x-axis are the points that have y-value equal to 0

<u>Checking the graph, we can note that</u> the function crosses the x-axis at two points which are (6,0) and (10,0)

<u>Part f:</u>

The point where the graph crosses the y-axis is the point that has x-value equal to 0

<u>Checking the graph, we can note that</u> the function crosses the y-axis at only one point which is (0,5)

<u>Part g:</u>

f(x) < 0 means that the output of the function (the y-value) is less than 0 (0 is not included)

Taking a look at the graph, we can note that the function has negative output on the interval from 6 (excluded) to 10 (excluded)

<u>In interval notation, this is written as</u> ]6 , 10[

<u>Part h:</u>

f(-7) means the output of the function (the y-value) at input (x-vale) equal to -7

From the graph, we can note that the function has a constant value of 5 starting from x=5 till -∞

<u>This means that</u>, at x=-7, the value of y is 5 which is a positive value

Hope this helps :)

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